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3 years ago

What is big dataplease explain why it is called big and do the data necessarily mean numbers

Computers and Technology

1 answer:

harkovskaia [24]3 years ago

6 0

Answer:

Big data is to analyze large complex data.

Explanation:

It is basically a data processing software which has overcome the disadvantage which we had in the classical software where it was not able to manage huge data in a faster mode.

The mean of an informational collection is found by including all numbers in the informational index and afterwards partitioning by the number of qualities in the set.

To answer the question is the word big points to a number? I would say yes, since it can handle large amount of data, it is so called “Big data.

The middle is the center worth when an informational collection is requested from least to most noteworthy. The mode is the number that happens frequently in an informational index.

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3 years ago

You have one ip address provided from your isp with a /30 mask. However, you have 300 users that need to access the internet. Wh

creativ13 [48]

Answer:

a. PAT

Explanation:

20.You have one IP address provided from your ISP with a /30 mask. However, you have 300 users that need toaccess the Internet. What technology will you use to implement a solution?a.PATb.VPNc.DNSd.VLANs

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2 years ago

Look at the code below. What does it do?

yulyashka [42]

Answer:

3- The code takes in an input, turns it into an integer and then multiplies it by 2 and prints it

Explanation:

Look- First, the code snippet asks for an input (int or float) as "Rawheight".

Aftewards, it converts the input into an integer numeral(if it was a float) and multiplies it by 2.

This processed value is, then, further transferred to the variable "double_height" and is thereafter rendered on the user's virtual screen.

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2 years ago

Define a function SetTime, with int parameters hoursVal and minutesVal, that returns a struct of type TimeHrMin. The function sh

Lapatulllka [165]

Answer:

#include <stdio.h>

typedef struct TimeHrMin_struct //struct

{

int hours;

int minutes;

} TimeHrMin;

struct TimeHrMin_struct SetTime(int hoursVal,int minutesVal) //SetTime function

{

struct TimeHrMin_struct str;

str.hours=hoursVal; //assigning the values

str.minutes=minutesVal;

return str; //returning the struct

}

int main(void)

{

TimeHrMin studentLateness;

int hours;

int minutes;

scanf("%d %d", &hours, &minutes);

studentLateness = SetTime(hours, minutes); //calling the function

printf("The student is %d hours and %d minutes late.\n", studentLateness.hours, studentLateness.minutes);

return 0;

}

Explanation:

4 0

3 years ago

We have said that the average number of comparisons need to find a target value in an n-element list using sequential search is

bija089 [108]

Answer:

Part a: If the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b: If the list contains n elements (where n is even) the middle terms are at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c: The average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

Explanation:

Suppose the list is such that the starting index is 0.

Part a

If list has 15 elements, the middle item would be given at 7th index i.e.

there are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(8,9,10,11,12,13,14) above it. It will have to run 8 comparisons to find the middle term.

If list has 17 elements, the middle item would be given at 8th index i.e.

there are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(9,10,11,12,13,14,15,16) above it.It will have to run 9 comparisons to find the middle term.

If list has 21 elements, the middle item would be given at 10th index i.e.

there are 10 indices (0,1,2,3,4,5,6,7,8,9) below it and 10 indices (11,12,13,14,15,16,17,18,19,20) above it.It will have to run 11 comparisons to find the middle term.

Now this indicates that if the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b

If list has 16 elements, there are two middle terms as one at would be at 7th index and the one at 8th index .There are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(9,10,11,12,13,14,15) above it. It will have to run 9 comparisons to find the middle terms.

If list has 18 elements, there are two middle terms as one at would be at 8th index and the one at 9th index .There are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(10,11,12,13,14,15,16,17) above it. It will have to run 10 comparisons to find the middle terms.

If list has 20 elements, there are two middle terms as one at would be at 9th index and the one at 10th index .There are 9 indices(0,1,2,3,4,5,6,7,8) below it and 9 indices(11,12,13,14,15,16,17,18,19) above it. It will have to run 11 comparisons to find the middle terms.

Now this indicates that if the list contains n elements (where n is even) the middle terms are at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c

So the average number of comparisons is given as

((n+1)/2+(n+2)/2)/2=(2n+3)/4

So the average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

6 0

3 years ago

What is big dataplease explain why it is called big and do the data necessarily mean numbers​

What is big dataplease explain why it is called big and do the data necessarily mean numbers