The cost of wallpaper used to cover all sides of the storage box is given by $3 per square foot
<h3>Cost of wallpaper per square foot</h3>
- length = 9 ft
- Width = 8 ft
- Height = 5 ft
Surface area of a box = 2(lh + wh + lw)
= 2(9×5 + 8×5 + 9×8)
= 2(45 + 40 + 72)
= 2(157)
= 314 square foot
- Total cost of wallpaper = $942
Cost of wallpaper per square foot = $942 ÷ 314 square foot
= $3 per square foot
Learn more about surface area:
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Answer: The answer is 381.85 feet.
Step-by-step explanation: Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.
This situation is framed very nicely in the attached figure, where
BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?
From the right-angled triangle WGB, we have
and from the right-angled triangle WAB, we have'
Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.
Thus, the height of the building across the street is 381.85 feet.
True
4x^2 -16x +16 = (2x -4)^2
A = 2x
B = 4
Answer:
The value of the ve = 9m/sec
Step-by-step explanation:
From the given formula, it can be conclude that this is evenly accelerated movement.
First I will rewrite given formula
vi = √ ve∧2 - 2ad First we will square on both sides and get
vi∧2 = ve∧2 - 2ad Now we will add monom (+2ad) to both sides and get
vi∧2 + 2ad = ve∧2 -2ad + 2ad =>
ve∧2 = vi∧2 +2ad Now we will rooted both sides and get
ve = √vi∧2 + 2ad
Now we will replace given data vi=7m/sec, a=8m/s∧2 and d=2m in the last formula
ve= √7∧2 + 2*8*2 = √49+32 = √81 = 9
ve= 9m/sec
Good luck!!!
