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3 years ago

When y= 234, x= 18. Find the value of x when y= 91.

Mathematics

1 answer:

andrew11 [14]3 years ago

5 0

Answer:

Step-by-step explanation:

Hey! So first divide 234 by 18 to find a ratio. You would get 13:1. So apply this to y=91. 91/13 is 7.

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If two angles in a triangle are 60° and 30°, is the third angle acute, obtuse, or right?

Sindrei [870]

Answer: Right Angle

Step-by-step explanation:

And Since The Angles Of a Trangle Add Up To 180° When You Substract 90 From It You Remain With Another 90° Which Means The Angle Is Non Other Than a right angle traingle

60° + 30° = 90°

180° - 90° = 90°

∴ 90° = Right Angle Traingle

4 0

3 years ago

I’m confused?????????

QveST [7]

Answer:

The equation of the line is y - 3 = 2.5(x - 2) ⇒ D

Step-by-step explanation:

The rule of the slope of a line is m = $\frac{y2-y1}{x2-x1}$ , where

(x1, y1) and (x2, y2) are two points on the line

The point-slope form of a line is y - y1 = m(x - x1), where

(x1, y1) is a point on the line

From the given figure

∵ The line passes through points (2, 3) and (0, -2)

∴ x1 = 2 and y1 = 3

∴ x2 = 0 and y2 = -2

→ Substitute them in the rule of the slope to find it

∵ m = $\frac{-2-3}{0-2}=\frac{-5}{-2}=2.5$

∴ m = 2.5

→ Substitute the values of m, x1, y1 in the form of the equation above

∵ m = 2.5, x1 = 2, y1 = 3

∵ y - 3 = 2.5(x - 2)

∴ The equation of the line is y - 3 = 2.5(x - 2)

6 0

3 years ago

The length l, width w, and height h of a box change with time. At a certain instant the dimensions are l = 3 m and w = h = 6 m,

Gemiola [76]

Answer:

a) The rate of change associated with the volume of the box is 54 cubic meters per second, b) The rate of change associated with the surface area of the box is 18 square meters per second, c) The rate of change of the length of the diagonal is -1 meters per second.

Step-by-step explanation:

a) Given that box is a parallelepiped, the volume of the parallelepiped, measured in cubic meters, is represented by this formula:

$V = w \cdot h \cdot l$

Where:

$w$ - Width, measured in meters.

$h$ - Height, measured in meters.

$l$ - Length, measured in meters.

The rate of change in the volume of the box, measured in cubic meters per second, is deducted by deriving the volume function in terms of time:

$\dot V = h\cdot l \cdot \dot w + w\cdot l \cdot \dot h + w\cdot h \cdot \dot l$

Where $\dot w$ , $\dot h$ and $\dot l$ are the rates of change related to the width, height and length, measured in meters per second.

Given that $w = 6\,m$ , $h = 6\,m$ , $l = 3\,m$ , $\dot w =3\,\frac{m}{s}$ , $\dot h = -6\,\frac{m}{s}$ and $\dot l = 3\,\frac{m}{s}$ , the rate of change in the volume of the box is:

$\dot V = (6\,m)\cdot (3\,m)\cdot \left(3\,\frac{m}{s} \right)+(6\,m)\cdot (3\,m)\cdot \left(-6\,\frac{m}{s} \right)+(6\,m)\cdot (6\,m)\cdot \left(3\,\frac{m}{s}\right)$

$\dot V = 54\,\frac{m^{3}}{s}$

The rate of change associated with the volume of the box is 54 cubic meters per second.

b) The surface area of the parallelepiped, measured in square meters, is represented by this model:

$A_{s} = 2\cdot (w\cdot l + l\cdot h + w\cdot h)$

The rate of change in the surface area of the box, measured in square meters per second, is deducted by deriving the surface area function in terms of time:

$\dot A_{s} = 2\cdot (l+h)\cdot \dot w + 2\cdot (w+h)\cdot \dot l + 2\cdot (w+l)\cdot \dot h$

Given that $w = 6\,m$ , $h = 6\,m$ , $l = 3\,m$ , $\dot w =3\,\frac{m}{s}$ , $\dot h = -6\,\frac{m}{s}$ and $\dot l = 3\,\frac{m}{s}$ , the rate of change in the surface area of the box is:

$\dot A_{s} = 2\cdot (6\,m + 3\,m)\cdot \left(3\,\frac{m}{s} \right) + 2\cdot (6\,m+6\,m)\cdot \left(3\,\frac{m}{s} \right) + 2\cdot (6\,m + 3\,m)\cdot \left(-6\,\frac{m}{s} \right)$

$\dot A_{s} = 18\,\frac{m^{2}}{s}$

The rate of change associated with the surface area of the box is 18 square meters per second.

c) The length of the diagonal, measured in meters, is represented by the following Pythagorean identity:

$r^{2} = w^{2}+h^{2}+l^{2}$

The rate of change in the surface area of the box, measured in square meters per second, is deducted by deriving the surface area function in terms of time before simplification:

$2\cdot r \cdot \dot r = 2\cdot w \cdot \dot w + 2\cdot h \cdot \dot h + 2\cdot l \cdot \dot l$

$r\cdot \dot r = w\cdot \dot w + h\cdot \dot h + l\cdot \dot l$

$\dot r = \frac{w\cdot \dot w + h \cdot \dot h + l \cdot \dot l}{\sqrt{w^{2}+h^{2}+l^{2}}}$

Given that $w = 6\,m$ , $h = 6\,m$ , $l = 3\,m$ , $\dot w =3\,\frac{m}{s}$ , $\dot h = -6\,\frac{m}{s}$ and $\dot l = 3\,\frac{m}{s}$ , the rate of change in the length of the diagonal of the box is:

$\dot r = \frac{(6\,m)\cdot \left(3\,\frac{m}{s} \right)+(6\,m)\cdot \left(-6\,\frac{m}{s} \right)+(3\,m)\cdot \left(3\,\frac{m}{s} \right)}{\sqrt{(6\,m)^{2}+(6\,m)^{2}+(3\,m)^{2}}}$

$\dot r = -1\,\frac{m}{s}$

The rate of change of the length of the diagonal is -1 meters per second.

6 0

3 years ago

Gabby packs 37 boxes with limes. Each box holds 10 lemons. How many limes can Gabby pack into these boxes?

Len [333]

Answer:

3 boxes with a remainder of 7 lemons left

6 0

3 years ago

Find the value of k so that (x + 3) a factor of H(x) = 3x ^ 3 - 2x ^ 2 + kx - 3

gavmur [86]

Step-by-step explanation:

By Factor Theorem, (x + 3) is a factor of H(x) if and only if H(-3) = 0.

3(-3)³ - 2(-3)² + (-3)k - 3 = 0

-81 - 18 - 3k - 3 = 0

3k = -102

k = -34.

4 0

3 years ago