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ioda
2 years ago
14

What is the factor for the expression - 3x + 6

Mathematics
1 answer:
Archy [21]2 years ago
5 0

Hello from MrBillDoesMath!

Answer:

3 ( -x + 2) is the factorization; 3 is the common factor

Discussion:

Each term in   -3x + 6 has 3 as a factor so the factorization is

3 ( -x + 2)


Thank you,

MrB

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What k-1/3=5/6 equal ?
JulijaS [17]
The value of "K"

k -\frac{1}{3} = \frac{5}{6}

MMC (3,6)
3,6 | 3
1,2 | 2
1,1 |__ 3*2 = 6

Solving:
k -\frac{1}{3} = \frac{5}{6}
\frac{6k}{6} - \frac{2}{6} = \frac{5}{6}
cancel denominators (6)
6k - 2 = 5
6k = 5+2
6k = 7
\boxed{k =  \frac{7}{6} }


7 0
3 years ago
Is 33,44,55 a right triangle?
Paul [167]

Answer:

Yes!

Step-by-step explanation:

We know that right triangles follow the Pythagorean Theorem, where

a^{2} + b^{2} = c^{2}

So we will put our side lengths into this formula, keeping in mind that c = the hypotenuse, which is the longest side. a and b are fairly arbitrary.

33^{2} + 44^{2} = 55^{2}

If this works, we know it's a right triangle.

1089 + 1936 = 3025

3025 = 3025

It worked! It's a right triangle!!

6 0
2 years ago
Read 2 more answers
MA = (4x - 2) and mzB = (11x + 17)°. Find x if the angles are
charle [14.2K]
The answer is a.) 165 sorry if that’s wrong but i hope it’s right
3 0
3 years ago
Read 2 more answers
(7)/(3) of it is 5 (5)/(6)
slava [35]

let's firstly convert the mixed fraction to improper fraction and then take it from there, keeping in mind that the whole is "x".

\stackrel{mixed}{5\frac{5}{6}}\implies \cfrac{5\cdot 6+5}{6}\implies \stackrel{improper}{\cfrac{35}{6}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{7}{3}x~~ = ~~5\frac{5}{6}\implies \cfrac{7}{3}x~~ = ~~\cfrac{35}{6}\implies 42x=105\implies x=\cfrac{105}{42} \\\\\\ x=\cfrac{21\cdot 5}{21\cdot 2}\implies x=\cfrac{21}{21}\cdot \cfrac{5}{2}\implies x=1\cdot \cfrac{5}{2}\implies x=2\frac{1}{2}

7 0
1 year ago
Can someone explain (with steps) how to rationalize the following expression?
insens350 [35]
F(x)=(-2/((x+y-2)^(1/2))-(x+y+2)^(1/2)
the only irrational part of this expression is the (x+y-2)^(1/2) in the denominator, so, to rationalize this, you multiply the numerator and denominator by the denominator, as well as the other parts of the expression
also, you must multiply the -sqrt(x+y+2) by sqrt(x+y-2)/sqrt(x+y-2) to form a common denominator
(-2)/(x+y-2)^(1/2)-(x+y+2)^(1/2)(x+y-2)^(1/2)/(x+y-2)^(1/2)
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(-2-(x^2+xy+2x+xy+y^2+2y-2x-2y-4))/(x+y-2)^(1/2)
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(Rationalize denominator by multiplying both top and bottom by sqrt)
(-x^2-y^2-2xy+2)((x+y-2)^(1/2))/(x+y-2)
(The function is now rational)
=(-x^2-y^2-2xy+2)(sqrt(x+y-2))/(x+y-2)
6 0
3 years ago
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