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Sav [38]
3 years ago
14

if the pressure on a 3.0 liter sample of gas is doubled at constant temperature, the new volume will be

Chemistry
2 answers:
BabaBlast [244]3 years ago
7 0
The new volume is 6.0 leters

k0ka [10]3 years ago
3 0

Answer : The new volume will be, 1.5 L

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = P

P_2 = final pressure = 2P

V_1 = initial volume = 3.0 L

V_2 = final volume = ?

Now put all the given values in the above equation, we get:

P\times 3.0L=2P\times V_2

V_2=1.5L

Thus, the new volume will be, 1.5 L

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Basile [38]

Answer:

2nd option

Explanation:

5 0
3 years ago
A solution is prepared by mixing 2.17 g of an unknown non-electrolyte with 225.0 g of chloroform. The freezing point of the resu
Deffense [45]

Answer:

The molar mass of the unknown non-electrolyte is 64.3 g/mol

Explanation:

Step 1: Data given

Mass of an unknown non-electrolyte = 2.17 grams

Mass of chloroform = 225.0 grams

The freezing point of the resulting solution is –64.2 °C

The freezing point of pure chloroform is – 63.5°C

kf = 4.68°C/m

Step 2: Calculate molality

ΔT = i*kf*m

⇒ ΔT = The freezing point depression = T (pure solvent) − T(solution) = -63.5°C + 64.2 °C = 0.7 °C

⇒i = the van't Hoff factor = non-electrolyte = 1

⇒ kf = the freezing point depression constant = 4.68 °C/m

⇒ m = molality = moles unknown non-electrolyte / mass chloroform

0.7 °C = 1 * 4.68 °C/m * m

m = 0.150 molal

Step 3: Calculate moles unknown non-electrolyte

molality = moles unknown non-electrolyte / mass chloroform

Moles unknown non-electrolyte = 0.150 molal * 0.225 kg

Moles unknown non-electrolyte = 0.03375 moles

Step 4: Calculate molecular mass unknown non-electrolyte

Molar mass = mass / moles

Molar mass = 2.17 grams / 0.03375 moles

Molar mass = 64.3 g/mol

The molar mass of the unknown non-electrolyte is 64.3 g/mol

6 0
3 years ago
Which hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine?
arsen [322]

The highlighted atoms have sp2 - sp3 hybridization. The highlighted atoms are carbon and nitrogen as shown.

The structure of Xanthine is shown in the image attached to this answer. The indicated atoms are Carbon and nitrogen as shown. Let us remember that hybridization has to do with the mixing of atomic orbitals to form appropriate hybrid orbitals that are suitable for overlap with orbitals of other atoms.

The highlighted carbon atom is sp2 hybridized because it has a carbon nitrogen double bond while the highlighted nitrogen atom is sp3 hybridized. Therefore, the highlighted atoms have sp2 - sp3 hybridization.

Learn more: brainly.com/question/22824409

4 0
2 years ago
Which of these describes a Mole in Chemistry?
olya-2409 [2.1K]

Answer: Thus the correct option is  D. All of the above describe a mole

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass in grams.

1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles.

Mole is the S.I unit for measuring the amount of substance. It is often used to measure large number of particles.

Thus the correct option is  D. All of the above describe a mole

5 0
2 years ago
What are the best note taking styles for high school?
photoshop1234 [79]

Answer:

cornell noted

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used in middle school and can be helpful for subjects like ela history and science

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