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Sav [38]
3 years ago
14

if the pressure on a 3.0 liter sample of gas is doubled at constant temperature, the new volume will be

Chemistry
2 answers:
BabaBlast [244]3 years ago
7 0
The new volume is 6.0 leters

k0ka [10]3 years ago
3 0

Answer : The new volume will be, 1.5 L

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = P

P_2 = final pressure = 2P

V_1 = initial volume = 3.0 L

V_2 = final volume = ?

Now put all the given values in the above equation, we get:

P\times 3.0L=2P\times V_2

V_2=1.5L

Thus, the new volume will be, 1.5 L

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The mass of a system does not change during a chemical reaction

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A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som
Andrews [41]

The given question is incomplete. The complete question is as follows.

A certain liquid has a normal boiling point of 124.2^{o}C and a boiling point elevation constant k_{b} = 0.62 ^{o}C kg mol^{-1}. A solution is prepared by dissolving some sodium chloride (NaCl) in 6.50 g of X. This solution boils at 127.4^{o}C. Calculate the mass of NaCl that was dissolved. Round your answer to significant digits.

Explanation:

As per the colligative property, the elevation in boiling point will be as follows.

     

T = boiling point of the solution =

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K_{b} = elevation of boiling constant = 0.62 ^{o}C kg mol^{-1}

We will calculate the molality as follows.

     molality = \frac{\text{maas of solute}}{\text{molar mass of solute}} \times \frac{1000}{\text{mass of solvent in g}}

i = vant hoff's factor

As NaCl is soluble in water and dissociates into sodium and chlorine ions so i = 2.

Putting the given values into the above formula as follows.  

    T - T_{o} = i \times K_{b} \times \text{molality of solution}

  (127.4 - 124.2)^{o}C = 2 \times 0.62 \times \frac{m}{60} \times \frac{1000}{650}

                  m = 100 g

Therefore, we can conclude that 100 g of NaCl was dissolved.

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Explanation: hope this answers your question

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