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Sav [38]
3 years ago
14

if the pressure on a 3.0 liter sample of gas is doubled at constant temperature, the new volume will be

Chemistry
2 answers:
BabaBlast [244]3 years ago
7 0
The new volume is 6.0 leters

k0ka [10]3 years ago
3 0

Answer : The new volume will be, 1.5 L

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = P

P_2 = final pressure = 2P

V_1 = initial volume = 3.0 L

V_2 = final volume = ?

Now put all the given values in the above equation, we get:

P\times 3.0L=2P\times V_2

V_2=1.5L

Thus, the new volume will be, 1.5 L

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What set of coefficients will balance the chemical equation: _NaBr (aq) + _H3PO4 (aq) → _Na3PO4(aq) + _HBr (aq)
GaryK [48]

The Balanced chemical equation for above reaction will be :

\small{ \mathrm{3NaBr + H_3PO_4 \rightarrow Na_3PO_4 + 3HBr}}

The Coefficients will be :

  • NaBr - 3

  • H_3PO_4 - 1

  • Na_3PO_4 - 1

  • HBr - 3

So, Correct option is :

A. 3, 1, 1, 3

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6 0
3 years ago
How many oxygen atoms are in an ozone molecule?
Margaret [11]
Molecular formula of Ozone is O3. Hence ozone molecule contains 3 oxygen atoms.

Hope this helps!
5 0
3 years ago
What mass of silver oxide, Ag2O is required to produce 25.0 g of silver sulfadiazine, AgC10H9N4SO2, from the reaction of silver
Wittaler [7]

Answer:

8.1107 g

Explanation:

The given reaction:

2C_{10}H_{10}N_4SO_2+Ag_2O\rightarrow 2AgC_{10}H_9N_4SO_2+H_2O

Given that:

Mass of silver sulfadiazine = 25.0 g

Molar mass of silver sulfadiazine = 357.14 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{25.0\ g}{357.14\ g/mol}

Moles= 0.07\ mol

From the reaction,

2 moles of silver sulfadiazine are formed from 1 mole of silver oxide

So,

1 mole of silver sulfadiazine are formed from 1/2 mole of silver oxide

0.07 mole of silver sulfadiazine are formed from 1/2*0.07 mole of silver oxide

Moles of silver oxide = 0.035 moles

Molar mass  of silver oxide = 231.735 g/mol

Mass = Moles * Molar mass = 0.035 moles * 231.735 g/mol = 8.1107 g

4 0
4 years ago
Click the "draw structure" button to launch the drawing utility. under certain reaction conditions, 2,3−dibromobutane reacts wit
REY [17]

Answer:

Explanation:

According to this. Let's analize the possible products a, b and c.

First, the problem states that we have 2 eq. of base, For this case, let's assume it's KOH. Now, As we are doing a reaction with base, means that this reaction can only take places under conditions of SN2 and E2, a fast reaction that is taking place in only 1 step.

With this in mind, let's analyze product a. This states that it has two sp hybridized carbon, in other words, a triple bond between two carbons. So the product is with no doubt, an alkyne.

Product b has only one sp hybridized carbon, which means that this carbon should cannot be an alkyne because we need two carbon atoms. The only way to have one atom of C sp hybridized, is with two double bonds, so product b would have to a alkene with two double bonds.

Product c do not have sp hybridized carbon, therefore, it only has two double bonds in two different Carbon atoms, so it's another alkene with two double bonds, but in two different atoms of carbon.

Picture attached show the product a, b and c. Hope this can help

4 0
3 years ago
The solubility of CO2 in water is 0.161 g/100 mL at 20oC and a partial pressure of CO2 of 760 mmHg. What partial pressure of CO2
Schach [20]

<u>Answer:</u> The partial pressure of carbon dioxide having solubility 0.886g/100mL is 4182.4 mmHg

<u>Explanation:</u>

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

The equation given by Henry's law is:

C_{CO_2}=K_H\times p_{CO_2}       ......(1)

where,

C_{CO_2 = solubility of carbon dioxide in water = 0.161 g/100 mL

K_H = Henry's constant = ?

p_{CO_2} = partial pressure of carbon dioxide = 760 mmHg

Putting values in equation 1, we get:

760mmHg=K_H\times 0.161g/100mL\\\\K_H=\frac{760mmHg}{0.161g/100mL}=4720.5g.mmHg/100mL

Now, calculating the pressure of carbon dioxide using equation 1, we get:

C_{CO_2 = solubility of carbon dioxide in water = 0.886 g/100 mL

K_H = Henry's constant = 4720.5 g.mmHg/100 mL

p_{CO_2} = partial pressure of carbon dioxide = ?

Putting values in equation 1, we get:

p_{CO_2}=4720.5g.mmHg/100mL\times 0.886g/100mL=4182.4mmHg

Hence, the partial pressure of carbon dioxide having solubility 0.886g/100mL is 4182.4 mmHg

4 0
3 years ago
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