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Sav [38]
3 years ago
14

if the pressure on a 3.0 liter sample of gas is doubled at constant temperature, the new volume will be

Chemistry
2 answers:
BabaBlast [244]3 years ago
7 0
The new volume is 6.0 leters

k0ka [10]3 years ago
3 0

Answer : The new volume will be, 1.5 L

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = P

P_2 = final pressure = 2P

V_1 = initial volume = 3.0 L

V_2 = final volume = ?

Now put all the given values in the above equation, we get:

P\times 3.0L=2P\times V_2

V_2=1.5L

Thus, the new volume will be, 1.5 L

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konstantin123 [22]

Answer:

the temperature of the star

Explanation:

The color of stars usually indicates the temperature of the star.

A star that is relatively cold usually shows a typical red color.

The hottest stars have a blue color.  

  • These star colors have been used by astronomers to determine their temperature.
  • A broad spectrum between blue, the hottest color,  and red the coldest is used.
  • Class O stars are usually the blue colored ones
  • Class M is the coldest with red color

8 0
2 years ago
Be(OH)2 is solid why?​
pickupchik [31]

Answer:

no it's not solid rather it's an aqueous

Explanation:

B/c Barium hydroxide is used in analytical chemistry for the titration of weak acids, particularly organic acids. Its clear aqueous solution is guaranteed to be free of carbonate, unlike those of sodium hydroxide and potassium hydroxide, as barium carbonate is insoluble in water.

8 0
1 year ago
Drag the tiles to the correct locations on the equation. Not all tiles will be used.
mel-nik [20]

Answer:

Tile 52 and three are incorrect

Explanation:

6 0
1 year ago
Michelle is trying to find the average atomic mass of a sample of an unknown
GREYUIT [131]

The average atomic mass of her sample is 114.54 amu

Let the 1st isotope be A

Let the 2nd isotope be B

From the question given above, the following data were obtained:

  • Abundance of isotope A (A%) = 59.34%
  • Mass of isotope A = 113.6459 amu
  • Mass of isotope B = 115.8488 amu
  • Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
  • Average atomic mass =?

The average atomic mass of the sample can be obtained as follow:

Average \: atomic \: mass \:  =  \frac{mass \: of \: A \times A\%}{100}  + \frac{mass \: of \: B \times B\%}{100}  \\  \\ Average \: atomic \: mass \:  =  \frac{113.6459\times 59.34}{100} + \frac{115.8488\times 40.66}{100} \\  \\ Average \: atomic \: mass \:  = 114.54 \: amu  \\  \\

Thus, the average atomic mass of the sample is 114.54 amu

Learn more about isotope: brainly.com/question/25868336

3 0
2 years ago
PLEASE HELP!! How could using either more or less of a chemical in a scientific experiment cause a change in results?
charle [14.2K]
The chemical could have more or less of a reaction to the other chemicals in the experiment
4 0
3 years ago
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