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Natalija [7]
3 years ago
11

Chloroform is a liquid once used for anesthetic. What is the volume of 5.0 g of chloroform? The density of chloroform 1.49 g/mL

Chemistry
1 answer:
mario62 [17]3 years ago
4 0

Answer:

3.3557047 mL

Explanation:

The density can be found using the following formula:

d=\frac{m}{v}

Let's rearrange the formula to find the volume, v.

d*v=\frac{m}{v}*v

d*v=m

\frac{d*v}{d} =\frac{m}{d}

v=\frac{m}{d}

The volume can be found by dividing the mass by the density. The mass of the chloroform is 5 grams and the density is 1.49 grams per milliliter. Therefore,

m= 5g \\d= 1.49 g/mL

Substitute the values into the formula.

v=\frac{5g}{1.49 g/mL}

Divide. When we divide, the grams, or g, in the numerator and denominator will cancel out.

v= \frac{5}{1.49}mL

v=3.3557047 mL

The volume of 5 grams of chloroform is 3.3557047 milliliters

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Answer:


First, the microwaves transmit kinetic energy to the water molecules of the food, heating the water molecules. Only, those that are not very deep into the food.


Second, the hot water molecules transmit heat by conduction to the other parts of the food.


Explanation:


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4) The microwaves transmit energy to the water molecules in the food, by increasing the kinetic energy of water molecules. As result, the water molecules get hotter. Microwaves only penetrate about 1 cm inside the food (a potato for example) and from that the heat is transferred by conduction to the inner parts of the food.

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Which element is chemically similar to chlorine?
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1 C8H10(l) +21/2O2(g) → 8CO2(g) + 5H2O(g), Hcomb= ? Hf for C8H10(l) = +49.0kJ/mol C8H10(l) Use the balanced combustion reaction
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Answer:

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Explanation:

Hello,

In this case, the enthalpy of combustion is understood as the energy released when one mole of fuel, in this case octene, is burned in the presence of oxygen and is computed with the enthalpies of formation of the fuel, carbon dioxide and water as shown below (oxygen is circumvented as it is a pure element):

H_{comb}=8*\Delta _fH_{CO_2}+5\Delta _fH_{H_2O}-\Delta _fH_{C_8H_{10}}

Thus, since we already know the enthalpy of combustion of the fuel, for carbon and water we have -393.5 and -241.8 kJ/mol respectively, thereby, the enthalpy of combustion turns out:

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Best regards.

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