Answer:
1. Potassium, K.
2. Calcium, Ca.
3. Gallium, Ga.
4. Carbon, C.
5. Bromine, Br.
6. Barium, Ba.
7. Silicon, Si.
8. Gold, Au.
Explanation:
Atomic radius can be defined as a measure of the size (distance) of the atom of a chemical element such as hydrogen, oxygen, carbon, nitrogen etc, typically from the nucleus to the valence electrons. The atomic radius of a chemical element decreases across the periodic table, typically from alkali metals (group one elements such as hydrogen, lithium and sodium) to noble gases (group eight elements such as argon, helium and neon). Also, the atomic radius of a chemical element increases down each group of the periodic table, typically from top to bottom (column).
Additionally, the unit of measurement of the atomic radius of chemical elements is picometers (1 pm = 10 - 12 m).
1. Li or K: the atomic radius of lithium is 167 pm while that of potassium is 243 pm.
2. Ca or Ni: the atomic radius of calcium is 194 pm while that of nickel is 149 pm.
3. Ga or B: the atomic radius of gallium is 136 pm while that of boron is 87 pm.
4. O or C: the atomic radius of oxygen is 48 pm while that of carbon is 67 pm.
5. Cl or Br: the atomic radius of chlorine is 79 pm while that of bromine is 94 pm.
6. Be or Ba: the atomic radius of berryllium is 112 pm while that of barium is 253 pm.
7. Si or S: the atomic radius of silicon is 111 pm while that of sulphur is 88 pm.
8. Fe or Au: the atomic radius of iron is 156 pm while that of gold is 174 pm.
The correct response is A. The inner she'll contains 2 electrons and the outer shell contains 4 electrons.
Answer:
See image attached and explanation
Explanation:
The reaction of phenol with SO3/H2SO4 is an electrophilic reaction. The electrophile attacks portions of high electron density in the substrate phenol.
The -OH group activates phenol towards electrophilic substitution at the ortho and para positions, hence the product(s) formed in this reaction(only one product is shown here as required by the question).
The sulphonation of phenol using concentrated sulfuric acid at lower temperature yields majorly the ortho product whereas at higher temperature the para product predominates.
<span>The answer should be Uranium. As tiny amounts of that (rods normally) can fuel a whole nuclear energy station for years.</span>
If you were to compare the mass of the products and reactants in a reaction, you would find that the mass of the products <span>is equal to the mass of the reactants.</span>
