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Nataly [62]
2 years ago
8

How are the molecules attached to each others?

Chemistry
1 answer:
kobusy [5.1K]2 years ago
4 0

ANSWER:

atoms with a positive charge will be negatively charged atoms to form a molecule.❤️

brainliest pls:)

#CARRY ON LEARNING#:)

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Which of these is a compound?<br><br> A. Steel<br><br> B.Sugar<br><br> C.Air<br><br> D.Nitrogen
hjlf

Sugar is a compound made of carbon, hydrogen and oxygen.

8 0
3 years ago
Read 2 more answers
When hydrated copper(II) sulfate crystals are heated, anhydrous copper(II) sulfate forms. A mass of 12.5 g of hydrated copper(II
pychu [463]

The formula of hydrated copper(II) sulfate is CuSO4.10H2O

<h3>What is the formula of the hydrated copper (ii) sulfate salt?</h3>

The formula of the hydrated copper (ii) sulfate is determined as follows:

Mass of hydrated salt = 12.5 g

Mass of anhydrous salt = 8.0 g

Mass of water = 12.5 - 8 = 4.5 g

mole ratio of water and anhydrous salt is;

4.5/18 : 8.0/159.5

0.562 : 0.05

10 : 1

Water of crystallization (n) = 10.

Therefore, the formula of hydrated copper(II) sulfate is CuSO4.10H2O

Learn more about water of crystallization at: brainly.com/question/26146814

#SPJ1

7 0
2 years ago
1. Write the name meaning
Kisachek [45]

Answer:

A.. 0.1 gram this means 0.0001kg of the object in SI unit

b. 0.01 meter this means 1 / 10 of 1 meter of the measurement

c. 0.000001 liter this means 1/10000 of the quality of liquid in SI unit

e. 1000 000 grams.this means 1000kg of the object in IS unit

L. 10 meters this means 10 times one meter of the measurement in SI unit

3 0
3 years ago
How much 2.0 M NH4NO3 is needed to make 0.585 L of 1.2 M NH4NO3 solution?
Nutka1998 [239]

Answer:

b . 0.351 L.

Explanation:

Hello!

In this case, since diluted solutions are prepared by adding an extra amount of diluent to a stock-concentrated solution, we infer that the number of moles of solute remains the same, therefore we can write:

C_1V_1=C_2V_2

Thus, solving for the volume of the stock solution, V1, we obtain:

V_1=\frac{C_2V_2}{C_1}

Now, by plugging in the given data we obtain:

V_1=\frac{1.2M*0.585L}{2.0M}\\\\V_1=0.351L

Therefore, the answer is b . 0.351 L.

Best regards!

5 0
2 years ago
A student weighs out a 6.64 g sample of , transfers it to a 500. mL volumetric flask, adds enough water to dissolve it and then
Vsevolod [243]

Answer:

the molarity of cobalt(II) fluoride in the resulting solution is = 0.137  M

Explanation:

Given that :

a student dissolves 6.64 g of CoF₂  into 500 mL of water

volume of the solution(water) = 500 mL = 0.50 L

The standard  molar mass of CoF₂ is 96.93 g/mol

number of moles of CoF₂ = mass of CoF₂/molar mass of CoF₂

number of moles of CoF₂ = 6.64 g/96.93 g/mol

number of moles of CoF₂ = 0.0685 mol

The molarity of any given substance is known to be as the number of moles of solute dissolved in one litre of solution.

Thus ;

Molarity of  cobalt(II) fluoride CoF₂ in the resulting solution is = number of moles / Volume in (L)

Molarity of  cobalt(II) fluoride CoF₂  = 0.0685 mol/ 0.50 L

= 0.137  M

Thus ; the molarity of cobalt(II) fluoride in the resulting solution is = 0.137  M

7 0
3 years ago
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