1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
anzhelika [568]
3 years ago
9

How many moles of FeCl3 could be produced from 6.1 moles of Cly? 2 Fe + 3Cl2 —> 2 FeCl2

Chemistry
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer:

4.1 moles of FeCl₃

Explanation:

The reaction expression is given as shown below:

         2Fe    +       3Cl₂   →    2FeCl₃

Number of moles of Cl₂  = 6.1moles

So;

  We know that from the balanced reaction expression:

                       3 moles of Cl₂ will produce 2 moles of FeCl₃

Therefore    6.1moles of Cl₂ will produce \frac{6.1 x 2}{3}   = 4.1 moles of FeCl₃

The number of moles is 4.1 moles of FeCl₃

You might be interested in
What is the change in internal energy ( ΔU ) of the system if q = –8 kJ and w = –1 kJ for a certain process?
Radda [10]

Answer:

Change in internal energy (ΔU) = -9 KJ

Explanation:

Given:

q = –8 kJ [Heat removed]

w = –1 kJ [Work done]

Find:

Change in internal energy (ΔU)

Computation:

Change in internal energy (ΔU) = q + w

Change in internal energy (ΔU) = -8 KJ + (-1 KJ)

Change in internal energy (ΔU) = -8 KJ - 1 KJ

Change in internal energy (ΔU) = -9 KJ

6 0
3 years ago
(Giving brainliest)
Aneli [31]
It would repel some of the negatively charged electrons of the wall so the answer would be C. The wall and the ballon repel each other
4 0
3 years ago
Read 2 more answers
15g of magnesium (II) oxide decomposes, find the number of oxygen particles produced at 100% yield.
erastova [34]

2.258625 *10²³ oxygen atoms will be produced.

<h3><u>Explanation:</u></h3>

Decomposition reaction is defined as the type of reaction where one single reactant breaks to produce more than one product only by means of heat or other external factor.

Formula of magnesium oxide = MgO.

The molecular mass of magnesium oxide = 24 +16= 40.

So in 40 grams of magnesium oxide, number of molecules is 6.023 * 10²³.

So in 15 grams of magnesium oxide,, number of molecules is 6.023 *1023 * 15/40 = 2.258625 *10²³.

From one molecule of magnesium oxide, one oxide atom will be produced.

So number of oxide atoms with 100% yeild = 2.258625 *10²³

6 0
3 years ago
2.<br> How many moles are contained in 0.800 g of calcium chloride (CaCl2)?
Ronch [10]
The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Calcium Chloride, or 110.984 grams.
7 0
3 years ago
Water molecules have a polarity, which allows them to be electrically attracted to other water molecules and other polar molecul
scZoUnD [109]
Hello there.

Water molecules have a polarity, which allows them to be electrically attracted to other water molecules and other polar molecules by weak chemical bonds known as
Hydrogen bonds
7 0
3 years ago
Read 2 more answers
Other questions:
  • Electrolysis breaks down water to form hydrogen and oxygen gas. The word equation that represents this reaction is
    12·2 answers
  • In a lab, the mass of object A is 2.5 kg. Object A weighs:
    9·2 answers
  • What are the reactants to burning paper and the products
    7·1 answer
  • Agree or disagree? Explain (2 ideas, 2 examples)
    15·1 answer
  • Monkeys and bats have similar bone structure in their forelimbs. However, monkeys have longer forelimbs to use for climbing and
    13·1 answer
  • A 1.540 gram sample of an alloy containing only tin and zinc was reacted with excess fluorine gas to produce 2.489 grams in tota
    15·1 answer
  • The train traveled 100 miles in 4 hours how fast was the train traveling
    10·2 answers
  • Determine the grams of barium chloride produced when 500 grams of barium hydroxide
    10·1 answer
  • What are five different types of air pollutant each
    10·1 answer
  • How many moles of HCl are required to neutralize 20.0 mL of 1.5 M KOH?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!