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GenaCL600 [577]
3 years ago
10

Conser the quadratic function f(x) = x^2 -8x - 4 what is the value of the leading coefficient

Mathematics
1 answer:
sasho [114]3 years ago
5 0

Answer:

The value of the leading coefficient is 1

Step-by-step explanation:

x^2 has the highest degree so the coefficient of this term is the leading coefficient.

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Answer as a fraction. do not include space in your answer.<br> 4 2/3 + 7/9
kvv77 [185]

Answer:

Step-by-step explanation:

4 2/3 = 14/3 x 3/3 = 42/9. 42/9 + 7/9 = 49/9. 49/9 = 5 4/9

42/9

3 0
2 years ago
-4/7 + 2/7x - 14x + 4/7
alexgriva [62]

Answer:

The solved given expression is

\frac{-4}{7}+\frac{2}{7}x-14x+\frac{4}{7}=\frac{-96x}{7}

Step-by-step explanation:

Given expression is \frac{-4}{7}+\frac{2}{7}x-14x+\frac{4}{7}

To solve the given expression :

\frac{-4}{7}+\frac{2}{7}x-14x+\frac{4}{7}

=\frac{-4+4+2x}{7}-14x

=\frac{0+2x}{7}-14x

=\frac{2x}{7}-14x

=\frac{2x-14x(7)}{7}

=\frac{2x-98x}{7}

=\frac{-96x}{7}

Therefore \frac{-4}{7}+\frac{2}{7}x-14x+\frac{4}{7}=\frac{-96x}{7}

Therefore the solved given expression is

\frac{-4}{7}+\frac{2}{7}x-14x+\frac{4}{7}=\frac{-96x}{7}

5 0
3 years ago
A Canadian television station shows 16 minutes of commercials every hour between 8:00 a.m. and 11:00 p.m. every day.
valentinak56 [21]

There are 16 minutes of commercials per hour from 8 A.M to 11 P.M

First, we have to find out how many hours is 8 A.M to 11 P.M

The hours are: 8, 9, 10, 11, 12, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, and 11.

So, it is 16 hours from 8 A.M to 11 P.M

Then, we multiply multiply 16 by 16 to find out how many minutes of commercials are in 16 hours.

16 x 16 = 256

So, there is 256 minutes of commercials in 16 hours.

Lastly, multiply 256 by 365 to see how many minutes of commercials are in one year.

256 x 365 = 93,440

Therefore, there are 93,440 minutes of commercials in a year.

8 0
3 years ago
Read 2 more answers
Find m Of the function
Masteriza [31]

Answer:

m=1

Step-by-step explanation:

slope formula is y=mx-b

whenever a variable is by itself, the coefficient is always 1

6 0
2 years ago
Having $ 200$200 today is equivalent to having what amount in one​ year?
Gnoma [55]
Suppose the interest rate is 4%, the equivalent of $200 in one year will be:
A=P(1+r/100)^n
where:
p=principle amount
r=rate
n=time
Hence the amount in 1 year will be:
A=200(1+4/100)^1
A=$208
Therefore $200 today is equivalent of $208 in 1 year.

4 0
3 years ago
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