How to find similarity between poloygons

1 answer:

5 0

For example, all equilateral triangles are similar and all squares are similar. If two polygons are similar, we know the lengths of corresponding sides are proportional. In similar polygons, the ratio of one side of a polygon to the corresponding side of the other is called the scale factor.

You might be interested in

Given the equation Square root of 2x plus 1 = 3, solve for x and identify if it is an extraneous solution. x = 4, solution is ex

Darya [45]

$\text{The domain:}\\2x+1\geq0\to 2x\geq-1\to x\geq-0.5\\\\D:x\geq0.5\to x\in\left\ \textless \ 0.5;\ \infty\right)\\\\\sqrt{2x+1}=3\ \ \ \ |\text{square both sides} \\2x+1=3^2\\2x+1=9\ \ \ |-1\\2x=8\ \ \ \ |:2\\x=4\in D\\\\\text{Answer: x =0, solution is not extraneous}.$

5 0

3 years ago

Read 2 more answers

The equation of a function<br>y = 2/3x+1/3 find the value of y<br>when x = -3<br>when x = 1 1/2

kirill [66]

Answer:

$y = \frac{-5}{3}\\\\y = \frac {4}{3}$

Step-by-step explanation:

$y = \frac{2}{3} x + \frac{1}{3}\\\\when \ x = -3 \\\\y = \frac{2}{3}(-3) + \frac{1}{3} = -2 + \frac{1}{3} = \frac{-6 + 1}{3}= \frac{-5}{3} \\\\When \ x = 1 \frac{1}{2} = \frac{3}{2}\\\\y = \frac{2}{3} \times \frac{3}{2} + \frac{1}{3} = 1+ \frac{1}{3} = \frac{3 + 1}{3}= \frac{4}{3} \\\\$