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lord [1]
3 years ago
5

Which graph represents the equation y = x-3?

Mathematics
2 answers:
AlekseyPX3 years ago
6 0

Answer:

The first

Step-by-step explanation:

The intercept is a negative so the line will be going the opposite way

liq [111]3 years ago
4 0

Answer:

c

Step-by-step explanation:

The equation shows that there is a positive slope of 1 and a y-intercept of -3. The only graph that shows those characteristics is c.

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Show work <br> Need fast!!! <br><br> 4(1/3+ 1/3+ 1/3)
aalyn [17]

Answer:

4

Step-by-step explanation:

calculate the sum 4*1 any expression is multiplied by 1 remains the same solution is 4

7 0
3 years ago
simplify, 6+3-3-3-3-3-21-5-5234-534-5-4-4-3-43-3-443--4-4-4-4--4-4-4-4-4-4-4--44-4--4-4-4=5647765865886*556386588668*56586856853
Nataly [62]

Answer:

−6294≠Infinity

Step-by-step explanation:

−6294≠Infinity

5 0
3 years ago
Which number line best shows how to solve -4-(-8)
Rama09 [41]

Answer:

The first point should be plotted at -4, then there should be a line that goes up 8 units and gives us a final destination of 4.

7 0
3 years ago
If I have a 93% as my subject grade and I get an 68% percent on a quiz as a quiz grade, what is my final subject grade.
trapecia [35]

Answer:

Password for the 1hdhhdhfhdhrhehjfujdjwjwjdjhf

Step-by-step explanation:

4 0
4 years ago
Solve the system by using a matrix equation (Picture provided)
Katyanochek1 [597]

Answer:

Option b is correct (8,13).

Step-by-step explanation:

7x - 4y = 4

10x - 6y =2

it can be represented in matrix form as\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}4\\2\end{array}\right]

A= \left[\begin{array}{cc}7&-4\\10&-6\end{array}\right]

X= \left[\begin{array}{c}x\\y\end{array}\right]

B= \left[\begin{array}{c}4\\2\end{array}\right]

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (7*-6) - (-4*10)

                                    = (-42)-(-40)

                                    = (-42) + 40 = -2

so, |A| = -2

Adj A=  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]

A⁻¹ =  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]/ -2

A⁻¹ =  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right]

X= A⁻¹ B

X=  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right] *\left[\begin{array}{c}4\\2\end{array}\right]

X= \left[\begin{array}{c}(3*4) + (-2*2)\\(5*4) + (-7/2*2)\end{array}\right]

X= \left[\begin{array}{c}12-4\\20-7\end{array}\right]

X= \left[\begin{array}{c}8\\13\end{array}\right]

x= 8, y= 13

solution set= (8,13).

Option b is correct.

3 0
3 years ago
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