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Rudik [331]
3 years ago
12

Brian pays £475.29 a year on his car insurance. The insurance company reduces the price by 2.1%.

Mathematics
2 answers:
ad-work [718]3 years ago
4 0
Decrease number 475.29 by 2.1% of its value: New value = 475.29 ... 475.29 = - 9.98109 Rounded to maximum 2 decimals: 475.29 decreased by 2.1% ≈ 465.31 ...
Nookie1986 [14]3 years ago
3 0

Answer:

470.12??? not sure!!!!

Step-by-step explanation:

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When 59,527 is divided by 23, the quotient is 2,588 R ____
Katyanochek1 [597]

Answer: the answer is 59,527 is divided by 23, the quotient is 2,588 R 3

the answer is 3 or remainder 3

Step-by-step explanation: brainlest please

3 0
3 years ago
At the end of each year, how much money would you earn in interest if you invested $200 and earned 5.5% simple interest?
Alborosie
\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$200\\
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7 0
3 years ago
2. Lab groups of three are to be randomly formed (without replacement) from a class that contains five engineers and four non-en
Anna11 [10]

Answer:

The number of different lab groups possible is 84.

Step-by-step explanation:

<u>Given</u>:

A class consists of 5 engineers and 4 non-engineers.

A lab groups of 3 are to be formed of these 9 students.

The problem can be solved using combinations.

Combinations is the number of ways to select <em>k</em> items from a group of <em>n</em> items without replacement. The order of the arrangement does not matter in combinations.

The combination of <em>k</em> items from <em>n</em> items is: {n\choose k}=\frac{n!}{k!(n-k)!}

Compute the number of different lab groups possible as follows:

The number of ways of selecting 3 students from 9 is = {n\choose k}={9\choose 3}

                                                                                         =\frac{9!}{3!(9 - 3)!}\\=\frac{9!}{3!\times 6!}\\=\frac{362880}{6\times720}\\ =84

Thus, the number of different lab groups possible is 84.

8 0
3 years ago
Can some one give th the right anwser and no website plz ill give u brainlynest
mash [69]

Answer:44

Step-by-step explanation:

Just you the proportions:

so you will get (20*33)/15 which is equals to 44

4 0
3 years ago
Read 2 more answers
4 cards are chosen at random from a deck of 52 cards without replacement. what's the probability of choosing a ten, a nine, an e
Dmitry_Shevchenko [17]

Answer:

12%

Step-by-step explanation:

im not sure so sorry if wrong

6 0
3 years ago
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