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4 years ago

State the most appropriate metric units to use to measure the width of an eyelash

Mathematics

1 answer:

liberstina [14]4 years ago

3 0

Hmmm A millimeter would be too big for that .
I think millionths of a meter would be about right. Micrometers.

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1/4(x+2)–1/3(x–1)=1/2(x+1)

Tanzania [10]

The answer is x=4/7 :)

7 0

3 years ago

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What is negative 6x squared take away 586 =84x take away 4

olchik [2.2K]

Answer:

This equation has no real roots

Step-by-step explanation:

We want to solve

$- 6 {x}^{2} - 586 = 84x - 4$

We group all terms on the left:

$- 6 {x}^{2} - 84x - 586 + 4 = 0$

$- 6 {x}^{2} - 84x - 582= 0$

Divide through by -6

${x}^{2} + 14x + 97 = 0$

The discriminant is

${14}^{2} - 4 \times 1 \times 97 = - 192$

This means the given equation has no real solution, since the discriminant is less than 0

6 0

3 years ago

H (t) = -t2 + t + 12 <br> Solve by using quadratic formula

Sedaia [141]

The quadratic formula is:

$x=\frac{-b+\sqrt{(b)^2-4(a)(c)}}{2a}$

and

$x=\frac{-b-\sqrt{(b)^2-4(a)(c)}}{2a}$

Let's identify our a, b, and c values:

a: -1

b: 1

c: 12

Plug in the values for a, b, and c into the equation. Let's do the first equation:

$x=\frac{-1+\sqrt{(1)^2-4(-1)(12)}}{2(-1)}$

Simplify everything in the radical:

$x=\frac{-1+\sqrt{49}}{-2}$

Simplify the radical:

$x=\frac{-1+7}{-2}$

Combine like terms:

$x=\frac{6}{-2}$

Simplify:

$x=-3$

This is one solution, now, let's solve for the other equation:

Since when simplified, everything is the same except the subtraction sign, we can skip the simplification again and change the sign to subtraction:

$x=\frac{-1-7}{-2}$

Combine like terms:

$x=\frac{-8}{-2}$

Simplify:

$x=4$

Your final answers are:

$x=-3$

$x=4$

8 0

3 years ago

Read 2 more answers

Help with geometry pls

Debora [2.8K]

Answer:

option 2 must be the correct answer because the two figure are congruent figure.

3 0

3 years ago

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Can someone please help me with these questions? I’m desperate! As always, I will give brainliest . I promise.

professor190 [17]

Since the centre of dilatation is the origin, we only require to multiply each of the coordinate points by the scale factor 3

(- 2, 1 ) → ( - 6, 3 )

(- 2, 3 ) → (- 6, 9 )

(1, 2 ) → (3, 6 )

(1, 3 ) → (3, 9 )

5 0

3 years ago