Answer:
1250 m²
Step-by-step explanation:
Let x and y denote the sides of the rectangular research plot.
Thus, area is;
A = xy
Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.
Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;
2x + y = 100
Thus, y = 100 - 2x
Since A = xy
We have; A = x(100 - 2x)
A = 100x - 2x²
At maximum area, dA/dx = 0.thus;
dA/dx = 100 - 4x
-4x + 100 = 0
4x = 100
x = 100/4
x = 25
Let's confirm if it is maximum from d²A/dx²
d²A/dx² = -4. This is less than 0 and thus it's maximum.
Let's plug in 25 for x in the area equation;
A_max = 25(100 - 2(25))
A_max = 1250 m²
Working attached below. Hope this helps! Any questions let me know :)
A=22/10
A=integral(a,b) [f(x)-g(x)]dx
Since the function is even (the function is mirrored over the y axis) we can evaluate the integral from 0 to 1 and then multiply our answer by 2 since we have the same area on each side of the y axis.
We get A=2*int.(0, 1)[(x^2)-(-2x^4)]dx
Now we can integrate by term.
2*[int.(0, 1)[x^2]dx+int(0, 1)[2x^4]dx]
Now factor out constants.
2*[int(0,1)[x^2]dx+2int(0,1)[x^4]dx]
Now integrate.
2*[(x^3/3)|(0,1) + 2*(x^5/5)|(0,1)]
Now solve.
2*[(1/3)+2*(1/5)]
=22/10
Hope you can decipher what I wrote!
Answer:
x = -4
Step-by-step explanation:
Lets work on this :D
(6x × 2) - 18x = 24
=>12x - 18x = 24
=> -6x = 24
=> x = -4
Please give me brainliest if this helped! :D
