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notka56 [123]
3 years ago
10

Rafael spins the pointers of the two spinners shown at the right. Find the probability of each possible sum.

Mathematics
1 answer:
Sloan [31]3 years ago
3 0

Answer:

P(sum 2)=1/6

P(sum 3)=1/3

P(sum 4)=1/3

P(sum 5)=1/6

Step-by-step explanation:

\left|\begin{array}{c|ccc}&1&2&3\\---&---&---&----\\1&2&3&4\\2&3&4&5\end{array}\right|

On the table, there are a  a total of 6 outcomes.

  • Number of sum that equals 2=1
  • Number of sum that equals 3=2
  • Number of sum that equals 4=2
  • Number of sum that equals 5=1

Therefore:

P(sum 2)=1/6

P(sum 3)=2/6=1/3

P(sum 4)=2/6=1/3

P(sum 5)=1/6

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Step-by-step explanation:

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Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. PEMDAS is the order of operations, and stands for:

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First, add 7 to both sides of the equation:

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