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notka56 [123]
3 years ago
10

Rafael spins the pointers of the two spinners shown at the right. Find the probability of each possible sum.

Mathematics
1 answer:
Sloan [31]3 years ago
3 0

Answer:

P(sum 2)=1/6

P(sum 3)=1/3

P(sum 4)=1/3

P(sum 5)=1/6

Step-by-step explanation:

\left|\begin{array}{c|ccc}&1&2&3\\---&---&---&----\\1&2&3&4\\2&3&4&5\end{array}\right|

On the table, there are a  a total of 6 outcomes.

  • Number of sum that equals 2=1
  • Number of sum that equals 3=2
  • Number of sum that equals 4=2
  • Number of sum that equals 5=1

Therefore:

P(sum 2)=1/6

P(sum 3)=2/6=1/3

P(sum 4)=2/6=1/3

P(sum 5)=1/6

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