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aev [14]
3 years ago
6

What is 35 cents times 500 ​

Mathematics
2 answers:
kvasek [131]3 years ago
7 0

Answer:

17500

Step-by-step explanation:

you just multiply it by 35 if it is pennies but you have to tell me if it is dimes or whatever

Yanka [14]3 years ago
7 0
175
.35 times 500 =175
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A simple random sample of 20 third-grade children from a certain school district is selected, and each is given a test to measur
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Answer:

Option C) 5.62 points  

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 20

Sample mean score = 64

Sample standard deviation, s = 12

Degree of freedom =

=n-1\\=20-1\\=19

We have to calculate margin of error for a 95% confidence interval.

Formula for margin of error:

t_{critical}\times \displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.05} = \pm 2.093  

2.093\times (\displaystyle\frac{12}{\sqrt{20}} )\\\\ =5.6161\approx 5.62  

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Option C) 5.62 points

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3 years ago
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111 is between 11 and 12
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Give an example of a function in everyday life and represent it
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For the given statement Pn, write the statements P1, Pk, and Pk+1.
Leno4ka [110]

Answer:

P_{1} =  2

P_{k} = k(k+1)

P_{k+1} = (k+1)(k+2)

Step-by-step explanation:

We are given the statement,

P_{n} as 2 + 4 + 6 + . . . + 2n = n(n+1)

That is,

P_{n} as 2 + 4 + 6 + . . . + 2n = \sum_{i=1}^{n}2i

So, we have,

P_{1} = \sum_{i=1}^{1}2i = 2

P_{k} = \sum_{i=1}^{k}2i = 2 + 4 + 6 + . . . + 2k = k(k+1)

P_{k+1} = \sum_{i=1}^{k}2i = 2 + 4 + 6 + . . . + 2k + 2(k+1) = (k+1)(k+2)

Thus, we get,

P_{1} =  2

P_{k} = k(k+1)

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7 0
3 years ago
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Please Help Meeeee!!! Will Mark Brainliest!!!
love history [14]

Answer:

Part A: Yes. For every 10 employees, an increase of 80 products produced.

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Step-by-step explanation:

Part A: 80 - 0 = 80 employees; 760 - 120 = 640 products. Therefore, 640/80 = 8 products per employee <u>or</u> 80 products per 10 employees

Part B: For y = mx + c ,

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c = Y-intercept, when X = 0. Therefore c = 120

3 0
2 years ago
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