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levacccp [35]
3 years ago
5

Find the polynomial of lowest degree with only real coefficients and having the given zeros. -7i and square root of 2

Mathematics
1 answer:
mario62 [17]3 years ago
7 0

Answer:

x³ - (√2)x² + 49x - 49√2

Step-by-step explanation:

If one root is -7i, another root must be 7i.  You can't just have one root with i.  The other roos is √2, so there are 3 roots.  

x = -7i       is one root,

   (x + 7i) = 0    is the factor

x = 7i       is one root

  (x - 7i) = 0     is the factor

x = √2      is one root

    (x - √2) = 0   is the factor

So the factors are...

(x + 7i)(x - 7i)(x - √2) = 0

Multiply these out to find the polynomial...

(x + 7i)(x - 7i) =  x² + 7i - 7i - 49i²

Which simplifies to

  x² - 49i²        since i² = -1 , we have

    x² - 49(-1)  

 

      x² + 49

Now we have...

(x² + 49)(x - √2) = 0

Now foil this out...

 x²(x) - x²(-√2) + 49(x) + 49(-√2) = 0

     x³ + (√2)x² + 49x - 49√2

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nikklg [1K]

Answer:

The constraints are as follows;

1) 2·x + 2·y ≤ 120

2) 3·x + 4·y ≤ 160

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4) y = 3.10

5) P = 2.3·x + 3.10

Step-by-step explanation:

The question is a word problem, with the analysis as follows;

The profit from the roast beef special per sandwich = $2.30

The profit from the turkey special per sandwich = $3.10

The number of slices of bread in the roast beef special = Two slices

The number of slices of cheese in the roast beef special = Three slices

The number of slices of bread in the turkey special = Two slices

The number of slices of cheese in the turkey special = Four slices

The number of slices of bread the deli has  = 120 slices

The number of slices of cheese the deli has = 160 slices

Let 'x' and represent the number of roast beef special and 'y' represent the number of turkey special the deli makes, then we have the constraints as follows;

For the number of slices of bread used;

2·x + 2·y ≤ 120...(1)

For the number of slices of cheese used;

3·x + 4·y ≤ 160...(2)

x = 2.30

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The profit 'P' is given by the following equation

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2 years ago
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