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Gre4nikov [31]
3 years ago
9

To calculate density, both _____ must be measured.

Physics
1 answer:
Mama L [17]3 years ago
7 0

Answer:

Mass & volume

Explanation:

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A coin is resting on the bottom of an empty container. The container is then filled to the brim three times, each time with a di
Virty [35]

Answer:

Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A

Explanation:

Let the depth of each section is h.

That means the real depth for each section is h.

Apparent depth is liquid A is 7 cm.

Apparent depth in liquid B is 6 cm.

Apparent depth in liquid C is 5 cm.

by the formula of the refractive index

n = real depth / apparent depth

where, n is the refractive index of the liquid.

For liquid A:

n_{A}=\frac{h}{7}    .... (1)

For liquid B:

n_{B}=\frac{h}{6}   ..... (2)

For liquid C:

n_{C}=\frac{h}{5}     ..... (3)

By comparing all the three equations

nc > nB > nA

Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A

5 0
3 years ago
It takes 6 seconds for a stone to fall to the bottom of a mine shaft. how deep is the shaft
Margaret [11]
You need the kinematic equation for distance as a function of acceleration:

d = [v(initial) *t] + 0.5a*t^{2}

where a = gravitational acceleration 9.8m/s^{2}
v(initial) = starting velocity
t = time of fall

if the stone started at rest then v(initial) = 0 making the equation simply 0.5a * t^{2}

Let me know if you still need further help :)
6 0
3 years ago
In the graph above, how does the acceleration at A compare with the acceleration at B?
abruzzese [7]
This is a speed/time graph.
The slope of the graph at each point is the time rate of change of speed
at that point, and THAT's the definition of the magnitude of acceleration.

The slope of the curve is zero at both ' A ' and ' B ', so acceleration is
zero at both of those points.

That seems to be exactly what choice-c says.
3 0
3 years ago
Read 2 more answers
A space craft is traveling in interplanetary space at a constant velocity. what is the estimated distance traveled by the space
mina [271]

Answer:

A. 2.30 x 10^2 kil

Explanation:

3/2 = 1.5 and 0.72/2 = 0.36

1.93 + 0.36 = 2.29

2.29 = about 2.30

7 0
3 years ago
A 70-kg astronaut (including spacesuit and equipment) is floating at rest a distance of 13 m from the spaceship when she runs ou
Keith_Richards [23]

Answer:

Explanation:

mass of the astronaut including the spacesuit, M=30

distance of astronaut from the spaceship, d = 13 m

mass of the oxygen tank, m = 3 kg

Speed of tank with respect to spaceship, v=15~m/s

a)

<u>Using the conservation of linear momentum:</u>

total momentum before collision = total momentum after collision

M.u=m.v+(M-m)v'

0=3\times 15+(70-15)\times v'

v'=0.82~m/s

b)

She mush hold her breath until she reaches the spaceship, i.e.

t=d/v'

t=13/0.82

t=15.89~s

4 0
3 years ago
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