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3 years ago

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Physics

1 answer:

Butoxors [25]3 years ago

4 0

Answer:

141.18 ohms

Explanation:

From the question given above, the following data were obtained:

Voltage (V) = 12

Current (I) = 0.085 A

Resistance (R) =?

The resistance needed can be obtained as follow:

V = IR

12 = 0.085 × R

Divide both side by 0.085

R = 12 / 0.085

R = 141.18 ohms

Therefore, a resistor of resistance 141.18 ohms is needed.

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A fish of 108 N is attached to the end of a dangling spring, stretching the spring by 14.0 cm. What is the mass of a fish that w

siniylev [52]

Answer:

The mass of the fish is 18.1 kg.

Explanation:

Given;

weight of the fish, F = 108 N

extension of the spring by the given weight, x = 14 cm = 0.14 m

First, determine the elastic constant of the spring by applying Hook's law;

F = kx

where;

k is the spring constant

k = F/x

k = 108 / 0.14

k = 771.43 N/m

When the spring is stretched to 23cm, the mass of the fish is calculated as follows;

$F = mg = Kx\\\\m = \frac{Kx}{g} \\\\m = \frac{771.43\times 0.23}{9.8} \\\\m = 18.1 \ kg$

Therefore, the mass of the fish is 18.1 kg.

4 0

3 years ago

A block with mass m =6.9 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.29 m.

crimeas [40]

1) The spring constant is 233.2 N/m

2) The oscillation frequency is 0.93 Hz

3) The speed of the block is 3.2 m/s

4) The maximum acceleration is $23.9 m/s^2$

5) The net force on the block is 104.9 N

Explanation:

At equilibrium, the weight of the mass is equal to the restoring force of the spring. Therefore, we can write:

$mg=kx$

where

m = 6.9 kg is the mass hanging on the spring

$g=9.8 m/s^2$ is the acceleration of gravity

k is the spring constant

x = 0.29 m is the stretching of the spring

Solving for k, we find

$k=\frac{mg}{x}=\frac{(6.9)(9.8)}{0.29}=233.2 N/m$

The oscillation frequency of a spring-mass system is given by

$f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}$

where

k is the spring constant

m is the mass

In this problem,

k = 233.2 N/m is the spring constant

m = 6.9 kg is the mass

Substituting, we find the frequency:

$f=\frac{1}{2\pi}\sqrt{\frac{233.2}{6.9}}=0.93 Hz$

The velocity of the block at time t is given by the equation:

$v(t) = -v_0 cos(\omega t)$

where

$v_0 = 4.1 m/s$ is the initial speed

$\omega$ is the angular frequency

t is the time

The angular frequency can be found from the frequency:

$\omega=2\pi f=2\pi(0.93)=5.84 rad/s$

And substituting t = 0.42 s, we find the velocity of the block at this time:

$v(t)=-4.1 cos ((5.84)(0.42))=3.2 m/s$

The maximum acceleration of the block is given by

$a_{max} = \omega^2 A$ (1)

where

$\omega=5.84 rad/s$ is the angular frequency

A is the amplitude

The amplitude is related to the initial velocity by the equation:

$v_0=\omega A$ (2)

Combining (1) and (2), we find

$a_{max}=v_0 \omega$

And substituting $v_0 = 4.1 m/s$ , we find

$a_{max}=(4.1)(5.84)=23.9 m/s^2$

The acceleration at time t can be found by calculating the derivative of v(t), and it is given by the equation

$a(t) = a_{max} sin(\omega t)$

where

$a_{max}=23.9 m/s^2$ is the maximum acceleration

$\omega=5.84 rad/s$ is the angular frequency

t is the time

Substituting t = 0.42 s,

$a(t)=(23.9)sin((5.84)(0.42))=15.2 m/s^2$

Finally, the net force on the block can be found by using Newton's second law:

$F=ma=(6.9)(15.2)=104.9 N$

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3 years ago

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Answer:

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3 years ago

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Eduardwww [97]

Answer: The machine must apply the force over a shorter distance. That's because a machine doesn't change the amount of work and work equals force times distance. Therefore, if force increases, distance must decrease

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3 years ago

A baseball has a mass of 0.15 kg and radius 3.7 cm. In a baseball game, a pitcher throws the ball with a substantial spin so tha

mylen [45]

Answer:

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Translational kinetic energy = 200 J

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