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4 years ago

What is the The most appropriate SI unit for measuring the length of an automobile

1 answer:

7 0

If you're talking about S.I. Unit then it must be "meter" (nothing else). Meter is the only S.I. Unit of length and it also uses in measuring the length of an automobile 'cause it varies from few meters to several thousand meters.

In short, Your Correct answer would be "meter" (m)

Hope this helps!

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The voltage leaving the secondary coil of a transformer is equal to 240 V. The secondary coil is wrapped 8 times around the core

Lina20 [59]

The initial voltage at the primary= 750 V

Explanation:

for a transformer

Es/ Ep= Ns/ Np

Es= secondary voltage= 240 V

Ep= primary voltage

Ns= number of turns in the secondary=8

Np= Number of turns in the primary=25

so 240/Ep=8/25

Ep=750 V

7 0

3 years ago

Read 2 more answers

What element is left over after the nuclear us reaction splits into different elements?

SVEN [57.7K]

Answer: A Radium

Explanation:

Thorium-232 is an alpha-emitting radionuclide, which decays to radium-228, which is a beta emitter with a half-life of about six years.

7 0

3 years ago

A 4-kilogram ball moving at 8 m/sec to the right collides with a 1-kilogram ball at rest. After the collision,

elena-14-01-66 [18.8K]

Conservation of momentum: total momentum before = total momentum after

Momentum = mass x velocity

So before the collision:
4kg x 8m/s = 32
1kg x 0m/s = 0
32+0=32

Therefore after the collision
4kg x 4.8m/s = 19.2
1kg x βm/s = β
19.2 + β = 32

Therefore β = 12.8 m/s

4 0

4 years ago

The root-mean-square speed (thermal speed) of the molecules of a gas is 200m/s at 23.0°C. At 227°C the root-mean-square speed (t

777dan777 [17]

Answer:

330 m/s approx

Explanation:

The RMS speed of a gas is proportional to square root of its absolute temperature is

V ( RMS ) ∝ √T

$\frac{V_1}{V_2} =\sqrt{\frac{T_1}{T_2} }$

Here V₁ = 200 , T₁ = 23 +273 = 300K , T₂ = 227 +273 = 500 K

Putting the values

200 / V₂ = $\sqrt{\frac{300}{500} }$

V₂ = 330 m/s approx

8 0

3 years ago

A small, spring-loaded cannon launches a tennis ball from level ground with an initial speed vi at an angle θi with the horizont

lora16 [44]

Answer:

a. $T\ =\ \dfrac{2v_isin\theta_i}{g}$

b. $v_icos\theta_i$

c. $v_1sin\theta_i$

Explanation:

Given,

*initial velocity of the ball = $v_i$

*angle of projection = \theta_i

Horizontal component of the initial velocity of the ball = $v_x\ =\ v_icos\theta_i$

vertical initial component of the initial velocity of the ball = $v_y\ =\ v_isin\theta_i$

part a

From the kinematics,

In the y-direction motion,

total vertical displacement of the ball during the whole motion is zero.

Ball is moving under the gravitational acceleration, therefore the acceleration of the ball = -g, because gravitational acceleration always acts in the downward direction,

Let t be the time of flight of the whole motion,

$y\ =\ v_yt\ -\ \dfrac{1}{2}gt^2\\\Rightarrow 0\ =\ v_isin\theta_i t\ -\ \dfrac{1}{2}gt^2\\\Rightarrow t\ =\ \dfrac{2v_isin\theta_i}{g}\\$

part b.

At the peak of the path of the ball, the vertical component of the velocity of the ball becomes zero, only horizontal component of the velocity acts on the ball is equal to = $v_x\ =\ v_icos\theta_i$

part c.

Initial vertical component of the velocity of the ball = $v_y\ =\ v_isin\theta_i$

5 0

3 years ago