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professor190 [17]
3 years ago
14

Help me :(( help me help me help me

Mathematics
2 answers:
iren2701 [21]3 years ago
7 0
With what ? Life ? I need help with that too
Alisiya [41]3 years ago
3 0
With what?idk what the question is.Is it where do u live, Whats ur adress,paypall me 283873$ or get a spider on ur head while u sleep
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There are approximatley 402 1/4 meters around a typical running track.sandra has challanged herself to run 10 laps a fay for 5 d
Lyrx [107]
402.25 * 10 = 4,022.5   Since there are five days and 10 laps per day, just multiply the second number by five    4,022.5 * 5  = 20,112.5 meters
5 0
3 years ago
This problem asks you to investigate the average value of some different quantities.
son4ous [18]

Answer:

429

Step-by-step explanation:

First You add 2+2 and then you add 205+123+101+7

3 0
3 years ago
Select the correct answer from each drop-down menu.
ruslelena [56]

The independent variable in the relationship is the <u><em>Number of Months</em></u> and should be placed on the<em> </em><u><em>x-axis</em></u>

The dependent variable in the relationship is the <em><u>Number of Fish</u></em> and should be placed on the <u><em>y-axis</em></u>

Step-by-step explanation:

Let us explain the independent and dependent variables of a relation

  • The independent variable is the input of the relation
  • The dependent variable is the output of the relation
  • The values of dependent variables depend on the values of independent variables
  • When the relation represented graphically the independent variable placed on the x-axis and the dependent variable placed on the y-axis

The table:

→ Number of Months:  0       :  1         :  2       :  3          :  4

→ Number of Fish      : 1,024 :  1,280 :  1600 :  2,000  :  2,500

Let us check is their any constant ratio between the consecutive values of the number of fish

∵ 1,280 ÷ 1,024 = 1.25

∵ 1,600 ÷ 1.280 = 1.25

∵ 2,000 ÷ 1,600 = 1.25

∵ 2,500 ÷ 2,000 = 1.25

∴ The table represent an exponential function, where the input

   is the number of months and the output is the number of fish

∵ The input is independent variable

∴ The independent variable is the number of months

∵ The output is the dependent variable

∴ The dependent variable is the number of fish

∵ The independent variable is placed on the x-axis

∴ The number of months should be place on the x-axis

∵ The dependent variable is placed on the y-axis

∴ The number of fish should be place on the y-axis

The independent variable in the relationship is the <u><em>Number of Months</em></u> and should be placed on the<em> </em><u><em>x-axis</em></u>

The dependent variable in the relationship is the <em><u>Number of Fish</u></em> and should be placed on the <u><em>y-axis</em></u>

<u><em /></u>

Learn more:

You can learn more about the relation in brainly.com/question/10708697

#LearnwithBrainly

6 0
3 years ago
JKLM is a rhombus. KM is 10 and JL is 24. Find the perimeter of the rhombus.
Ahat [919]
Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units

5 0
3 years ago
Fill the blank bellow.....
Lemur [1.5K]

slope = (y2-y1)/(x2-x1)

the first slope is 0 (horizontal line)

second slope is undefined (vertical line)

3 0
3 years ago
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