Question

the perimeter of am equilateral triangle is 7 inches more than perimeter of a square and the side of the triangle is 5 inches more than the side of the square. find the side of the triangle​

Answer 1

Let $t$ be the side of the triangle and $s$ be the side of the square.

Let $P_t$ be the perimeter of the triangle and $P_s$ be the perimeter of the square.

We have the following relationship:

$\begin{cases}P_t = P_s+7\\t=s+5\\P_t = 3t\\P_s=4s\end{cases} \implies \begin{cases}3t=4s+7\\t=s+5\end{cases} \implies 3(s+5)=4s+7 \implies s=8$

Which finally implies

$t=s+5=13$

Answer 2

Answer:

Side of triangle =  13 inches

Step-by-step explanation:

Let side of square be x inches.

Perimeter of square = 4*side = 4x   --------->1

side of triangle = x+5  { the side of the triangle is 5 inches more than the          side of the square. }

Perimeter of triangle = 3*side

                                   = 3 * (x+5)  =3x + 15 -------->2

The perimeter of an equilateral triangle is 7 inches more than perimeter of a square.

             3x + 15 - 4x = 7

                 3x -4x     = 7-15

                         -x     = - 8

x= 8

Side of a square = 8 inches.

Side of triangle = x + 5 = 8 + 5 = 13 inches