Triangle ABC is congruent to triangle XYZ. Angle A measures 50 degrees, angle B measure 2x+40 degrees, and angle Z measures 4x+8
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The value of the cosine function is -0.385
<h3>How to determine the measure of the cosine function?</h3>The figure that completes the question is added as an attachment
From the figure, we have the following sides
AB = √13
AC = 3
BC = 2
The triangle is a right triangle.
The angle B is calculated as:
cos(B) = 2/√13
Evaluate
cos(B) = 0.5547
Take the arccos of both sides
B = 56.31
This means that:
cos(ABC) = cos(56.31)
Multiply ABC by 2.
So, we have:
cos(ABC * 2) = cos(56.31 * 2)
Evaluate the product
cos(ABC * 2) = cos(112.62)
Evaluate the cosine
cos(ABC * 2) = -0.385
Hence, the value of the cosine function is -0.385
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