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2 years ago

6

Why have I been blocked?

1 answer:

Ivanshal [37]2 years ago

8 0

I’m not sure blocked from what

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Help please im struggling.

Hunter-Best [27]

Answer:

D. 2,2

Step-by-step explanation:

The midpoint just means the point in the middle of the line, and if you count inwards from each of the points, you'll find that D is the midpoint.

4 0

1 year ago

Read 2 more answers

Express the ratio 425 miles on 17 gallons of gas as a unit rate

Mariulka [41]

The answer is 25:1 or 25 to 1. They are the same thing thought.

7 0

2 years ago

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What is<br> as a decimal rounded to 3 decimal places?

puteri [66]

“Three decimal places” is the same as “the nearest thousandth.” So, for example, if you are asked to round 3.264 to two decimal places it means the same as if your are asked to round 3.264 to the nearest hundredth. Some questions, like the example below, will ask you to “show your answer correct to two decimal places."

7 0

2 years ago

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

2 years ago

Which of the following conditions must be met to conduct a two-proportion significance

katrin [286]

Hello, I Am BrotherEye

Answer: C.) 111 Only

Step-by-step explanation:

7 0

2 years ago