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3 years ago

Mathswhat is 0.000965 to :2 d.p1d.p2s.g.f3s.g.f thanks

1 answer:

4 0

Decimal places mean we just start counting immediately after the decimal point, so:
2dp: 0.00
1dp: 0.0

Significant figures, we start counting starting at the first non zero number
So we start counting at the 9, therefore:
2sf: 0.00097
3sf: 0.000965

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The grocery store sells kumquats for $5.00 a pound and Asian pears for $3.25 a pound. Write an equation in standard form for the

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3 years ago

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Factor completely. ay^2 + 2ay - 3a

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3 years ago

Which of the following is equal to the expression above

EleoNora [17]

Answer:

$15 \sqrt[3]{2}$

Step-by-step explanation:

${(27 \times 250)}^{ \frac{1}{3} } = {(27 \times 125 \times 2)}^{ \frac{1}{3} } \\ = {27}^{ \frac{1}{3} } \times {125}^{ \frac{1}{3} } \times {2}^{ \frac{1}{3} } \\ = \sqrt[ 3]{27} \times \sqrt[3]{125} \times \sqrt[3]{2} \\ = \sqrt[3]{ {3}^{3} } \times \sqrt[3]{ {5}^{3} } \times \sqrt[3]{2} \\ = 3 \times 5 \times \sqrt[3]{2} \\ = 15 \sqrt[3]{2}$

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3 years ago

(-9) x 7? Can't figure it out

mihalych1998 [28]

-56

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2 years ago

Noelle and Micah went to the bank to open new checking accounts. The equation C=0.2n+1.20 represents the monthly cost, C, in dol

Kaylis [27]

Answer:

C = $2.40

n = 6

Step-by-step explanation:

For Noelle,

Equation that represents the monthly cost 'C',

C = 0.2n + 1.20

Here, n = number of checks written in a month

For Micah,

Monthly cost for writing checks 'C' = $1.20

Number of checks 'n' = 3

Since, Cost of writing checks ∝ Number of checks written

C' ∝ n

C' = kn

k = $\frac{C'}{n}$

Here, k = proportionality constant

For C' = 1.2 and n = 3

k = $\frac{1.2}{3}$

k = 0.4

Equation will be,

C' = 0.4n

For any month C = C'

Therefore, 0.2n + 1.20 = 0.4n

0.4n - 0.2n = 1.20

0.2n = 1.20

n = 6

Number of checks written by Noelle and Micah = 6

For n = 6,

C = 0.2(6) + 1.20

C = $2.40

Cost of writing checks = $2.40

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3 years ago