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3 years ago

Plzz helpp Find the inverse function

Mathematics

1 answer:

Vesna [10]3 years ago

8 0

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$f(x) = {x}^{2} + 5$

$y = {x}^{2} + 5$

${x}^{2} + 5 = y$

Subtract sides 5

${x}^{2} + 5 - 5 = y - 5$

${x}^{2} = y - 5$

$x = ± \sqrt{y - 5}$

$x≠ - \sqrt{y - 5}$

Because x is a positive number but -√y-5 is a negative number thus it's unacceptable.

So ;

$x = \sqrt{y - 5}$

_________________________________

${f}^{ - 1}(x) = \sqrt{x - 5}$

Done...

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