The identity property is shown
Call the number : x
(1/3)x + 5 = x-6
=> (1/3)x + 5 - (x-6) = 0
=> (1/3)x + 5 - x + 6 = 0
Group (1/3)x with -x, 5 with 6
=> [(1/3)x - x] + (5+6) = 0
=> (-2/3)x + 11 = 0
=> (-2/3)x = -11
=> x = -11 : (-2/3) = 33/2.
Recheck : 1/3 x 33/2 + 5 = 33/6 + 5 = 63/6 = 21/2
33/2 - 21/2 = 12/2 = 6 (21/2 is 6 less than 33/2, satisfied.)
Answer: 10/14
Step-by-step explanation:
Answer:
0<=x<10 or [1,10)
Step-by-step explanation:
You need to solve this using logarithms. I will use natural logarithms (LN on your calculator)
15,000 is the initial price of the car because 0.88^0=1.
All we need is 0.88^x>0.1
Remember that the logarithm of a^b is b*LN(a).
x*LN(0.88)>LN(0.1)
x<LN(0.1)/LN(0.88)
The relation changes from > to < because we are dividing by LN(0.88) which is negative.
The calculator now yields
LN(0.1)/LN(0.88)=10
So, x<10 years. But you buy the car at x=0, hence the relevant domain is.
0<=x<10 or [1,10)
