Answer:
-4.99
1.9435
3.25E4
1.56e-9
Step-by-step explanation:
Answer:
1. Substitute y = -3x +4 for y in the first equation
2. Combine like terms and isolate x
3. Substitute in x into the 2nd equation to get y
Step-by-step explanation:
1. Substitute y = -3x +4 for y in the first equation
2x- (-3x+4) = 6
2. Combine like terms
5x -4 = 6
5x -4 +4 = 6+4
5x=10 Divide by 5 to isolate x
5x/5 =10/5
x=2
3. Substitute in x into the 2nd equation to get y
y = -3x +4
y = -3(2) +4
y = -6+4
y=-2
(2,-2)
Answer:
D. 4
Step-by-step explanation:
Since the only two corresponding side you have are 10 units and 4 units, you can divide these two numbers to get the scale factor.
10÷4=2.5
next you find the sides corresponding to X Y and Z and if it is on the bigger figure you divide, if it is on the smaller side you multiply
X corresponds with 5 (so ×2.5)
Y corresponds with 8 (÷2.5)
Z corresponds with 10 (÷2.5)
final answer is X=12.5 Y=3.2 Z=4
I try to explain the question and give the answer, I hope this helps!
Answer:
C
Step-by-step explanation:
In general for arithmetic sequences, recursive formulas are of the form
aₙ = aₙ₋₁ + d,
and the explicit formula (like tₙ in your problem), are of the form
aₙ = a₁ + (n - 1)d,
where d is the common difference. So converting between the two of these isn't so bad. In this case, your problem wants you to have an idea of what t₁ is (well, every answer says it's -5, so there you are) and what tₙ₊₁ is. Using the formulas above and your given tₙ = -5 + (n - 1)78, we can see that the common difference is 78, so no matter what we get ourselves into, the constant being added on at the end should be 78. That automatically throws out answer choice D.
But to narrow it down between the rest of them, you want to use the general form for the recursive formula and substitute (n + 1) for every instance of n. This will let you find tₙ₊₁ to match the requirements of your answer choices. So
tₙ₊₁ = t₍ₙ₊₁₎₋₁ + d ... Simplify the subscript
tₙ₊₁ = tₙ + d
Therefore, your formula for tₙ₊₁ = tₙ + 78, which is answer choice C.
