9.) The relation can not be a function only if the domain is the same. If you plot the points on a graph and use the Vertical Line Test(VLT) you would see that none of the points would be on the same line. It doesn't matter if the range is the same
10.)On the graph your y-intercept would be 2 so that is where you plot your first point. In order to find the slope you need to go up three spaces and one space to the left this is also known as "rise over run". *Remember you always go up spaces for "rise over run" but if the slope is positive then you go to the right and if its negative you go to the left.
I hope this helps love! :)
The linear model for the data is expressed as: R = 20p - 160.
<h3>How to Write a Linear Model?</h3>
Using two pairs of values from the table values, say, (32, 480) and (33, 500), find the unit rate (m).
Unit rate (m) = (500 - 480)/(33 - 32) = 20/1
Unit rate (m) = 20.
Substitute (p, R) = (32, 480) and m = 20 into R = mp + b to find b
480 = 20(32) + b
480 = 640 + b
480 - 640 = b
b = -160
To write the linear model, substitute m = 20 and b = -160 into R = mp + b:
R = 20p - 160
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Answer:
B.) 1/7
Step-by-step explanation:
you have a total of 15 the you subtract one so you have
15-1= 14
you had 3 dimes and you took one out so you have
3-1=2
so you have 2/14 and in simplest for that is 1/7 because you divide both by 2
I hope this was good enough:
Answer:
−5xy^2+y^3+25x^2−5xy−y^2
Step-by-step explanation:
25x^2−5xy−5xy^2+y^3−y^2=
25x^2−5xy−2
———————————-
Hi there!
We can use the following equation:
z = amount of standard deviations away a value is from the mean (z-score)
σ = standard deviation
x = value
μ = mean
Plug in the knowns for both and rearrange to solve for the mean:
Other given:
Set both equal to each other and solve:
