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3 years ago

What are the next three terms of the geometric sequence 4, 24, 144, . . . ?

Mathematics

2 answers:

telo118 [61]3 years ago

7 0

864,5184,31104 are the next three terms in the geometric sequence

alexgriva [62]3 years ago

4 0

144x6=864....4th number
864x6=5164.....5th number
5164x6= 31104....6th number

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-5+|-15÷(-5) |2(-5)

pav-90 [236]

Answer:

The value of this expression is -35.

Step-by-step explanation:

Let's use the order of operations (PEMDAS), to solve this problem.

$-5+|-15/-5|*2*(-5)\\-5+3*-10\\-5+-30\\-35$

In conclusion, the value of this expression is -35. Hope this helped :D

7 0

4 years ago

The same price of an item is $48 after a 40% discount what was the original price

Sonja [21]

Let, the original price = x
It would be: x*60% = 48
x = 48 / 0.60
x = 80

In short, Your Answer would be $80

Hope this helps!

8 0

3 years ago

Jack and Jill live 126 km apart. They want to leave their homes at the same time,

Digiron [165]

Answer:

Both will leave their homes to meet on time at 9 am

Step-by-step explanation:

Given as, Distance between Jack and Jill = 126 km

Speed of Jack rides = 18 kilometers per hours

Speed of Jill rides = 24 kilometers per hours

Let the distance travel by Jack = x km

And the distance travel by Jill = (126 - x ) km

Time taken by Jack and Jill = T hours

Now , Distance = Speed × Time

So, x = 18 × T

And 126 - x = 24 × T

Or, 126 - x = 24 × $\frac{x}{18}$

Or, 126 - x = x × $\frac{4}{3}$

Or, 378 - 3x = 4x

Or, 378 = 7x

i.e x = $\frac{378}{7}$ = 54 km

And distance travel by Jill = 126 - 54 = 72 km

So, time taken by Jack = $\frac{x}{18}$ = $\frac{54}{18}$

Or, Time taken by Jack = 3 hours

Similarly Time take by Jill = $\frac{72}{24}$ = 3 hours

∵ Both Jack and Jill will take 3 hours to meet at 12 : 00 pm

Hence, Both will leave their homes to meet on time at 9 am Answer

7 0

4 years ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago

What’s the measure of JKL?

lana [24]

check the picture below.

recall that a full circle has 360°.

6 0

4 years ago

Read 2 more answers