All categories

3 years ago

X = 3y - 6 2x - 4y = 8 Solve the system of equations using substitution.

2 answers:

8 0

Equation 1) x = 3y - 6
Equation 2) 2x - 4y = 8

Subtract 3y from both sides of the first equation.

1) x - 3y = -6

Then, multiply all of the first equation by 2.

1) 2(x - 3y = -6)

1) 2x - 6y = -12
2) 2x - 4y = 8

Subtract equations.

-2y = -20

Divide both sides by -2.

y = 10

Plug in 10 for y in the first equation.

x = 3y - 6

x = 3(10) - 6

x = 30 - 6

x = -24

(10,24)

~Hope I helped!~

Brut [27]3 years ago

7 0

Hello

x = 3y - 6
2x - 4y = 8
We need to start by solving 3y - 6 for x
Substitute 3y -6 for x in 2x
2x - 4y = 8
2(3y - 6) - 4y = 8
2y - 12 = 8
2y = 8 + 12
2y = 20
Divide both sides by 2
2y/2 = 20/2
y = 10

Now, substitute 10 for y in x= 3y
x = 3y - 6
x = 3(10) - 6
x = 30 - 6
x= 24

Answer : x = 24 and y=10

I hope this help!

You might be interested in

A recipe requires 2 eggs 500 grams of flour and two teaspoons of salt how many eggs are needed if you use 2 kg of flour?

Andre45 [30]

The explanation is here

5 0

2 years ago

Is .3333333333333 a rational number??

natali 33 [55]

Answer: No

Step-by-step explanation: Because it is.

8 0

3 years ago

Read 2 more answers

The parallelogram shown represents a map of the boundaries of a natural preserve. Walking trails run from points A to C and from

Citrus2011 [14]

y+2 = 3y-4 =

y+6 = 3y

6 =2y

y = 3

y+2 = 3+2 = 5

3y-4 = 3(3)-4 = 5

5+5 =10

2y-3 = 2(3) - 3 = 3

3+3 = 6

10+6 = 16 miles

answer is C

4 0

4 years ago

Read 2 more answers

Find the area of the region enclosed by the graphs of the functions

Vaselesa [24]

Answer:

$\displaystyle A = \frac{8}{21}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Functions
Function Notation
Graphing
Solving systems of equations

Calculus

Area - Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

*Note:

Remember that for the Area of a Region, it is top function minus bottom function.

Step 1: Define

f(x) = x²

g(x) = x⁶

Bounded (Partitioned) by x-axis

Step 2: Identify Bounds of Integration

Find where the functions intersect (x-values) to determine the bounds of integration.

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

Lower bound: -1

Upper Bound: 1

Step 3: Find Area of Region

Integration

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx$
[Area] Rewrite [Integration Property - Subtraction]: $\displaystyle A = \int\limits^1_{-1} {x^2} \, dx - \int\limits^1_{-1} {x^6} \, dx$
[Area] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = \frac{x^3}{3} \bigg| \limit^1_{-1} - \frac{x^7}{7} \bigg| \limit^1_{-1}$
[Area] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = \frac{2}{3} - \frac{2}{7}$
[Area] Subtract: $\displaystyle A = \frac{8}{21}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Area Under the Curve - Area of a Region (Integration)

Book: College Calculus 10e

6 0

3 years ago

What does K=Y/X stand for and mean?

Mamont248 [21]

Answer:

(k = y/x) which is the constant ratio between two proportional quantities y/x denoted by the symbol k which may be a positive rational number. The x value is directly proportional to the y value such as in the equation y = kx.

Step-by-step explanation:

the meaning of it means constant of proportionality

8 0

3 years ago