X = 3y - 6 2x - 4y = 8 Solve the system of equations using substitution.
2 answers:
Equation 1) x = 3y - 6 Equation 2) 2x - 4y = 8 Subtract 3y from both sides of the first equation. 1) x - 3y = -6 Then, multiply all of the first equation by 2. 1) 2(x - 3y = -6) 1) 2x - 6y = -12 2) 2x - 4y = 8 Subtract equations. -2y = -20 Divide both sides by -2. y = 10 Plug in 10 for y in the first equation. x = 3y - 6 x = 3(10) - 6 x = 30 - 6 x = -24 (10,24) ~Hope I helped!~
Hello x = 3y - 6 2x - 4y = 8 We need to start by solving 3y - 6 for x Substitute 3y -6 for x in 2x 2x - 4y = 8 2(3y - 6) - 4y = 8 2y - 12 = 8 2y = 8 + 12 2y = 20 Divide both sides by 2 2y/2 = 20/2 y = 10 Now, substitute 10 for y in x= 3y x = 3y - 6 x = 3(10) - 6 x = 30 - 6 x= 24 Answer : x = 24 and y=10 I hope this help!
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X=(5/4)^-10
Step-by-step explanation:
(5/4)^6÷x=(25/16)^8
(5/4)^6÷x=(5/4)^16
1/X==(5/4)^16÷(5/4)^6
X=(5/4)^6÷(5/4)^16
X=(5/4)^-10
So the value of X is (5/4)^-10
Parentheses affect how equations are done. EX. 1+1*4 4+1=5 VS (1+1)*4 2*4=8