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ValentinkaMS [17]
2 years ago
11

Help please I need help with this (And don't just put random stuff to steal my points)

Mathematics
1 answer:
PtichkaEL [24]2 years ago
6 0

Answer:

b

Step-by-step explanation:

i had to do this one in class and this is what i had gotten

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Three U.S coins add to $1 If one of them is not half a dollar what is the smallest value coin?
Svet_ta [14]
The smallest value is $0.25 (a quarter) because you can use two quarters and a half dollar. Only one of them can't be a half dollar, but the other two can be.
4 0
3 years ago
Sara travels often for her job. The miles she traveled for the last seven work days are shown. 88, 72, 91, 65, 86, 93, 97 Which
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Answer:

21

Step-by-step explanation:

3 0
3 years ago
Find the six arithmetic means between 1 and 29.
sp2606 [1]
1, ___, ____, _____, _____, _____, ____, 29

29-1 = 28
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1, 5, 9, 13, 17, 21, 25, 29
7 0
3 years ago
If a random sample of size nequals=6 is taken from a​ population, what is required in order to say that the sampling distributio
goldenfox [79]

Answer:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And we want a normal distribution for the sample mean

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

So for this case we need to satisfy the following condition:

X_i \sim N(\mu , \sigma), i=1,2,...,n

Because if we find the parameters we got:

E(\bar X) =\frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n}=\mu

Var(\bar X)= \frac{1}{n^2} \sum_{i=1}^n Var(X_i) = \frac{n\sigma^2}{n^2}= \frac{\sigma^2}{n}

And the deviation would be:

Sd (\bar X) = \frac{\sigma}{\sqrt{n}}

And we satisfy the condition:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

3 0
3 years ago
What would you measure in centimeters pool or fish tank
vfiekz [6]
Because pools are normally very large, you would use a larger unit, like meters, to measure it. Fish tanks are usually a lot smaller than pools, so you would use a smaller unit to measure them, like centimeters.
Your answer is a fish tank.
4 0
3 years ago
Read 2 more answers
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