H-j=4(h+j)-7 how do I get the answer for this? (solving for a variable)

1 answer:

8 0

Hey sweetheart so to solve for the variable:
Let's solve for h:
Add-4h to both sides
h-j=4(h+j)-7
h-j+-4h=4h+4j-7+-4h
-3h-j=4j-7
Add j to both sides
-3h-j+j=4j-7+j
-3h=5j-7
Then divide by 3
-3h/-3=5j-7/-3
so h=-5/3j+7/3

:)

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The sum of three consecutive odd integers is at most 123. Find the pair with the greatest sum

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Answer:

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Step-by-step explanation:

Let the first integer be a1 = a.

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The sum of three consecutive odd integers is 123.

123 = a1 + a2 + a3

123 = a + (a + 2) + (a + 4)

123 = 3a + 6

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