What is the length of EF in the right triangle below? 25
2 answers:
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We first need to determine whether we are dealing with means or proportions in this problem. Since we are given the sample and population mean, we know that we are dealing with means.
Since we have one sample mean, this means we are creating a confidence interval for one sample (1 Samp T Int).
Normally we would check for conditions, but since this is not formulated as a "real-world scenario" type problem, it is hard to check for randomness and independence. Therefore, I will be excluding conditions from this answer.
<h3>Confidence Interval Formula</h3>The formula for constructing a <u>confidence interval for means</u> is as follows:
We are given these variables:
Plug these values into the formula for the confidence interval:
In order to find t*, we can use this formula:
Calculating the z-score associated with "A" will give us t*.
So, let's plug in the confidence interval 95% (.95) into the formula:
Use your calculator or a t-table to find the z-score associated with this area under the curve.. you should get:
Now, let's finish the confidence interval we created:
We can calculate the confidence interval, using this formula, to be:
We are 95% confident that the true population mean μ lies between <u>47.4697 and 52.5303</u>.
Answer:
The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88
The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.
Step-by-step explanation:
Test if the proportion of times that luggage is returned within 24 hours is less than 0. 88
At the null hypothesis, we test if the proportion is of 0.88, that is:
At the alternate hypothesis, we test if this proportion is less than 0.88, that is:
The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
0.88 is tested at the null hypothesis:
This means that
A consumer group who surveyed a large number of air travelers found that 138 out of 160 people who lost luggage on that airline were reunited with the missing items by the next day.
This means that
Test statistic:
P-value of the test:
The p-value of the test is the probability of finding a sample proportion below 0.8625, which is the p-value of z = -0.68.
Looking at the z-table, the p-value of z = -0.68 is of 0.2483.
The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.