Question:
Find numbers a and k so that x-2 is a factor of

and

Answer:
and 
Step-by-step explanation:
Given



Required
Find a and k
For 
Substitute -1 for x





Substitute 3 for f(-1)

Collect Like Terms


Also:
If
is a factor, then

Substitute 2 for x and 0 for f(x)





Collect Like Terms



Substitute 12a - 14 for k in 


Collect Like Terms


Solve for a


Substitute 1 for a in 



1,265 divided by 34 is 37.20
You can't put a fraction of a book on a shelf so each shelf will have ABOUT 37 books
Make sure you include ABOUT in your answer
ANSWER

EXPLANATION
The given expression is

This is the same as:

In index notation, we write this as

To write this as a negative index, we use the property:

This implies that;

Answer:
The domain of relation is {1,3,5}
It is not a function.
Step-by-step explanation:
Given the relation {(1, 4), (3, 6), (5, 4), (1, 8)}
We need to find the domain and determine if the given relation is function or not.
The domain of relation is {1,3,5}
But the given relation is not function because we have x=1 twice in the relation and the for the relation to be function the values of domain can't be repeated.
So, It is not a function.