Answers:
Row 1: No, No, No
Row 2: Yes, Yes, Yes
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Explanation:
Use the vertical line test. If it is at all possible to draw a single vertical line through more than one point on the relation curve, then the relation is not a function. This is because a function is only possible when any x input leads to exactly one y output.
So that's why graphs 1,2,3 are not functions, while graphs 4,5,6 are functions.
<span>a. m∠L=58.1m∠L=58.1, m∠T=88.5m∠T=88.5, m∠D=33.4m∠D=33.4</span>
Answer: x = 16, x = 8
Step-by-step explanation:
|a| > 0, there are two solutions
|a| = 0, there is one solution
|a| < 0, there are no solutions
So, in this problem, we have two solutions.
In absolute value, the expression inside can be equal to itself OR its opposite.
Ex: |y| = y, |y| = -y
So, we can write two equations:
x - 12 = 4, x = 16
-x+12 = 4, x = 8
Check: |16 - 12| = |4| = 4
Check: |8 - 12| = |-4| = 4
sin 51 = BC / 58
BC = 58 sin 51
= 45.07 to nearest hundredth.
Its D
Answer:
(a) (a² +3a -1)(a² -3a -1)
Step-by-step explanation:
The constant term of the product of the factors will be equal to the product of their constants. Since you want that product to be +1, the signs of the factor constants must be the same. That eliminates choices (c) and (d).
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To tell which of choices (a) and (b) is correct, we can compute the squared term in their product. Let's do it in a generic way, with the constant (±1) being represented by "c".
We want the a² term in the product ...
(a² +3a +c)(a² -3a +c)
That term will be the result of multiplying both sets of first and last terms, and adding the product of the middle terms:
(a²·c) +(a²·c) -9a² = a²(2c-9)
So, we want the factor (2c-9) to be -11, which means c=-1, not +1.
The correct factorization of the given expression is ...
(a² +3a -1)(a² -3a -1) . . . . matches choice A
