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3 years ago

WILL MARK BRAINLIEST

1 answer:

7 0

To make this new triangle I am going to pretend that the original triangle was at the points (4,4) (-4,4) and (0,8). So if this was dilated down by 1/2 then the triangles points would be (2,2) (-2,2) and (0,4). Then if it is reflected over the x-axis the new points would be (2,-2) (-2,-2) and (0,-4) and if it was translated left by 2 units then the points would be (0,-2) (-4,-2) and (-2, -4), then if the triangle was translated up by 4 units the points and the new triangle would be (0,2) (-4,2) and (-2,0). And that would be what the new triangle would be.

The triangle went from (4,4) (-4,4) and (0,8) to (0,2) (-4,2) and (-2,0).

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The length of a rectangle is 5 inches shorter than 3 times the width. Which expression represents the length of the rectangle in

Karo-lina-s [1.5K]

Answer:

The answer is 3w-5

Step-by-step explanation:

First you would have to figure out what 3 times the width is which would be the 3w part then to fine the length you would subtract 5 since it is 5 inches shorter

6 0

2 years ago

Read 2 more answers

How much simple interest is earned on an investment of 1,250 if the money is invested for 5 years at an annual interest rate of

Alekssandra [29.7K]

<h3>Answer: $281.25</h3>

Work Shown:

i = P*r*t

i = 1250*0.045*5

i = 281.25

8 0

1 year ago

What is the center of the circle that you can circumscribe about a triangle with vertices A(2, 6), B(2, 0), and C(10, 0)?

denis23 [38]

The three points A,B,C are all points on this circle.
Each point is then equal distance from the center, that distance being the radius of the circle.
Using the distance formula, we can find the center of the circle (x,y):
$d^2 = (x-x_0)^2 + (y-y_0)^2$
Plugging in points A and B into distance formula, then setting them equal to each other gives:
$(x-2)^2+(y-6)^2 = (x-2)^2 + y^2$
Right away we can cancel out the x terms leaving:
$(y-6)^2 = y^2$
Expand Left side and Solve for y:
$y^2 -12y +36 = y^2$
$y = 3$
Plug in points B and C as before:
$(x-2)^2 + y^2 = (x-10)^2 + y^2$
Here we can cancel the y-terms.
Expand and solve for x:
$x^2 -4x+4 = x^2 -20x+100$
$16x = 96$
$x = 6$
Therefore the center of the circle is the point (6,3)

6 0

3 years ago

The area of the isosceles triangle is 80 square centimeters. Use the equation 1/2(8h) =80 to find the height of the triangle.

Dmitry [639]

Answer:

20cm

Step-by-step explanation:

Given data

Area= 80cm^2

we know that the expression for the area of a triangle is

A= 1/2B*H

from the given expression 1/2(8h) =80 the base is 8cm

let us substitute to find the height h

1/2(8h) =80

4h=80

h= 80/4

h= 20cm

Hence the heigth h is 20cm

6 0

2 years ago

What is the equation of a line that is parallel to -3x+4y=4 and passes through the point (4,0)

Andrei [34K]

Answer:

y = 3/4x - 3

Step-by-step explanation:

If you write the equation in slope-intercept form, you will need the slope(m) and the y-intercept(b):

y = mx + b

To solve this, you first need to know the slope of the line in the given equation. In order to do this, change it to slope-intercept form for easy analyzation:

-3x + 4y = 4

= 4y = 3x + 4

= y = 3/4x + 1

Now, you know the slope(m) is 3/4, so you have this much of the slope-intercept equation:

y = 3/4x + b

At this point, you need to find the y-intercept. This can be done by plugging in the given point in the equation and solving for b:

using (4, 0) and y = 3/4x + b,

(0) = 3/4(4) + b

0 = 3 + b

b = -3

So, that means that the equation for the line is:

y = 3/4x - 3

6 0

2 years ago