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3 years ago

Is D. the right answerPlease I need help

Mathematics

2 answers:

Licemer1 [7]3 years ago

7 0

Yes u are correct good job

lisov135 [29]3 years ago

6 0

Answer:

Yes its correct!

Step-by-step explanation:

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One student begins in Cleveland, Ohio, and walks towards Buffalo, New York, a distance of 200 miles. She walks at the rate of 2.

omeli [17]

Ok so student in cleveland walks 2.5 miles away from cleveland every hour from 8
so the distance, x is x=2.5t

the riding one rides 4 hours later, so t-4
11 mph
y=11(t-4)

A. x=2.5t
y=11(t-4)

when do they meet is when the distance when they are equal or when x=y
2.5t=x=y=11(t-4)
solve for t
2.5t=11(t-4)
2.5t=11t-44
-8.5t=-44
divide both sides by -8.5
t=5.17647

answer is 5.18 hours

A.
x=2.5t
y=11(t-4)

B. 5.18 hours

6 0

3 years ago

2 3 + 6^{2} ÷ 9 i need help with this one

creativ13 [48]

Answer: 7

Step-by-step explanation:

3+6^(2) / 9

3 + 36 / 9

3 + 4

5 0

3 years ago

Please Help!! Give Brainly!! What is the value of (14^0) ^-2? -1/196 1/196 0 1

Trava [24]

Answer:

so option 1 is correct

Step-by-step explanation:

$(14^0) ^-2$

power 0 * -2 = 0

if power is 0 then it equals to 1 so

$14^0$

= 1

8 0

3 years ago

Find four distinct complex numbers (which are neither purely imaginary nor purely real) such that each has an absolute value of

Luda [366]

Answer:

0.5 + 2.985i
1 + 2.828i
1.5 + 2.598i
2 + 2.236i

Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

$|C| = \sqrt{a^2+b^2}$

Then, the work consists in finding pairs (a,b) for which:

$\sqrt{a^2+b^2}=3$

You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

$\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}$

I will use b =0.5, b = 1, b = 1.5, b = 2

$b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236$

Then, four distinct complex numbers that have an absolute value of 3 are:

0.5 + 2.985i
1 + 2.828i
1.5 + 2.598i
2 + 2.236i

4 0

4 years ago

What is (2n+2)(6n+1)

tia_tia [17]

FOIL (distriute)
tells how to multiply which ones
First terms
Inner terms
Outer terms
Last terms

(2n+2)(6n+1)
First (2n times 6n=12n^2)
Inner (2 times 6n=12n)
Outer (2n times 1=2n)
Last (2 times 1=2)

add them
12n^2+12n+2n+2
12n^2+14n+2

4 0

4 years ago

Is D. the right answerPlease I need help​

Is D. the right answerPlease I need help