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LiRa [457]
3 years ago
5

If q is the smallest composite number greater than 2 and p is the smallest prime number less than 10, what is p/q? a. 2 b. 0.5 c

. 4 d. 1
Mathematics
1 answer:
Mrac [35]3 years ago
6 0

Answer:

b. 0.5

Step-by-step explanation:

knowing that a prime number is an integer with exactly two divisors and a composite number is an integer with more than two divisors, we have that if q is a composite number greater than 2 these can be 4, 6, 8, .. But how the smallest of them should be is 4, and  p is a prime number can be 2,3,5,7,....

but  is the smallest prime number less than 10 then p=2, also p/q=2/4 = 0.5

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Find the measurement of the indicated angle to the nearest degree
MaRussiya [10]

Answer:

42

Step-by-step explanation:

This time, you'll be doing SOH.

sin (x) = 39/59=0.66

then do sin^-1 (0.66)

x = 42 degrees (think this is correct I hope)

4 0
3 years ago
If h(x)=(fog)(x) and h(x)=³√x+3, find g(x) if f(x) =³√x+2
ipn [44]

Answer:

g(x)=x+1

The problem:

Find g(x) if h(x)=(f \circ g)(x),

h(x)=\sqrt[3]{x+3}, and

f(x)=\sqrt[3]{x+2}.

Step-by-step explanation:

h(x)=(f \circ g)(x)

h(x)=f(g(x))

Replace x in f(x)=\sqrt[3]{x+2} with g(x) since we are asked to find f(g(x)):

\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}

\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}

This implies that x+1=g(x)

Let's check:

(f \circ g)(x)

f(g(x))

f(x+1)

\sqrt[3]{(x+1)+2}

\sqrt[3]{x+1+2}

\sqrt[3]{x+3}  which is the required result for h(x).

6 0
3 years ago
Solve the inequality.<br> 140 &lt; -20j
klemol [59]

Answer:

              J < -7

Explantion:

Rewrite so J is on the left side

                  -20j > 140

               Divide each term by -20 and simplify

                   j < -7          

8 0
2 years ago
Determine the horizontal, vertical, and slant asymptotes: y=x2+2x-3/x-7
densk [106]

Answer:

  • vertical asymptote: x = 7
  • slant asymptote: y = x+9

Step-by-step explanation:

The vertical asymptotes are found where a denominator factor is zero (and there is no corresponding numerator factor to cancel it). Here, that is at x = 7.

There is no horizontal asymptote because the numerator is of higher degree than the denominator.

When you divide the numerator by the denominator, you get ...

  y = (x +9) +60/(x -7)

Then when x gets large, the behavior is governed by the terms not having a denominator: y = x +9. This is the equation of the slant asymptote.

3 0
3 years ago
Solve the equation 18y – 17 = 7 for y. <br><br> A. 1/2 <br> B. 3/4 <br> C. 4/3 <br> D. 4/5
Ivan

the answer is C. 4/3

3 0
3 years ago
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