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2 years ago

How long will it take a car at 85 mile to reach one mile?

2 answers:

7 0

Speed = 85miles/h
distance 1000miles
time?
speed= distance/time so time is distance/speed
time= 1000/85= 11hours and 46 minutes

Mariulka [41]2 years ago

7 0

If you mean 85 mph then the answer is 42 seconds

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Which statement describes the behavior of the function f(x)=3x/4-x?

Oksana_A [137]

Answer:

The graph approaches –3 as x approaches infinity. Option a is correct.

Step-by-step explanation:

The given function is

$f(x)=\frac{3x}{4-x}$

We have to find value of function as x approaches infinity. Take limit both sides as x approaches to infinity.

$\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3x}{4-x}$

Taking x common from the denominator.

$\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3x}{x(\frac{4}{x}-1)}$

Cancel out common factor x.

$\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3}{\frac{4}{x}-1}$

Apply limits.

$\lim_{x\rightarrow \infty}f(x)=\frac{3}{\frac{4}{\infty}-1}$

$\lim_{x\rightarrow \infty}f(x)=\frac{3}{0-1}$

$\lim_{x\rightarrow \infty}f(x)=-3$

Therefore the graph approaches –3 as x approaches infinity.

7 0

3 years ago

Read 2 more answers

What is (c+1) +9 in simplified form plz help

Afina-wow [57]

=(c+1)+9
=C+1+9
=C+10
10c

7 0

3 years ago

Read 2 more answers

Suppose the object moving is Dave, who hasamassofmo =66kgatrest. Whatis Daveâs mass at 90% of the speed of light? At 99% of the

nignag [31]

Step-by-step explanation:

Formula that relates the mass of an object at rest and its mass when it is moving at a speed v:

$m=\frac{m_o}{\sqrt{1-\frac{v^2}{c^2}}}$

Where :

m = mass of the oebjct in motion

$m_o$ = mass of the object when at rest

v = velocity of a moving object

c = speed of the light = $3\times 0^8 m/s$

We have :

1) Mass of the Dave = $m_o=66 kg$

Velocity of Dave ,v= 90% of speed of light = 0.90c

Mass of the Dave when moving at 90% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.90c)^2}{c^2}}}$

m = 151.41 kg

Mass of Dave when when moving at 90% of the speed of light is 151.41 kg.

2) Velocity of Dave ,v= 99% of speed of light = 0.99c

Mass of the Dave when moving at 99% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.99c)^2}{c^2}}}$

m = 467.86 kg

Mass of Dave when when moving at 99% of the speed of light is 467.86 kg.

3) Velocity of Dave ,v= 99.9% of speed of light = 0.999c

Mass of the Dave when moving at 99.9% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.999c)^2}{c^2}}}$

m = 1,467.17 kg

Mass of Dave when when moving at 99.9% of the speed of light is 1,467.17 kg.

4) Mass of the Dave = $m_o=66 kg$

Velocity of Dave,v=?

Mass of the Dave when moving at v speed of light: 500

$500 kg=\frac{66 kg}{\sqrt{1-\frac{(v)^2}{(3\times 10^8 m/s)^2}}}$

$v=2.973\times 10^8 m/s$

Dave should be moving at speed of $2.973\times 10^8 m/s$ .

4 0

3 years ago

PLEASE HELP MEEEEEEEE IM BEGGING

suter [353]

PLEASE HELP MEEEEEEEE IM BEGGING

4 0

2 years ago

Read 2 more answers

Alice has two bags of marbles: Bag A contains 8 red and 3 blue marbles, and Bag B contains 5 red and 7 blue marbles. She randoml

Thepotemich [5.8K]

It might help to draw out a probability tree. Check out the diagram below. The first two branches at the top represent bags A and B. The probability of picking either bag is 1/2 assuming each bag is equally likely to be picked.

If we go with bag A, then the probability of getting blue is 3/11 since there are 3 blue out of 8+3 = 11 total. The probability of getting bag A and a blue marble is (1/2)*(3/11) = 3/22 which I've marked in the diagram as well.

If we go with bag B, then the probability of getting blue is 7/12 since there are 7 blue out of 5+7 = 12 total. The probability of getting bag B and blue is (1/2)*(7/12) = 7/24

Add up the results found getting

P(blue) = P(blue & bag A) + P(blue & bag B)

P(blue) = 3/22 + 7/24

P(blue) = 36/264 + 77/264

P(blue) = 113/264

This is shown in the diagram as well.

--------------------------------------------------

Recall that conditional probability in general is defined as follows

P(A given B) = P(A and B)/P(B)

In this problem, we'll have

P(bag B given blue) = P(bag B and blue)/P(blue)

Therefore, we can say...

P(bag B given blue) = P(bag B and blue)/P(blue)

P(bag B given blue) = (7/24)/(113/264)

P(bag B given blue) = (7/24)*(264/113)

P(bag B given blue) = (7*264)/(24*113)

P(bag B given blue) = (7*24*11)/(24*113)

P(bag B given blue) = (7*11)/(113)

P(bag B given blue) = 77/113

In short, the probability of getting bag B, given the marble is blue, is 77/113.

8 0

2 years ago