The line has a positive slope. Let's look at all the slopes:
1) -3
2) -3
3) 3
4)3
Which ones are positive? That's right, 3 and 4. We don't know which equation would be the equation of the line. That's where the other information comes in.
The line intersects the y-axis at at a point that has a negative y-coordinate. Lets write the last two equations in slope-intercept form.
1) y = -3/2x - 5/2
2) y = -3/2x + 5/2
We have to graph both of the lines now. The graphs are at the very bottom. Take a look at them. In the first one, the y-intercept is a negative and in the second one, the y-intercept is positive.
The third one AKA 3x + 2y = -5 is the equation of the line. I hope this helps! Let me know if I got it wrong or if you need any more help.
The best answer the question above is D.
The answer is C. That would be ur answer
Answer:
Where is the N in the equation
Answer:
111°
Step-by-step explanation:
Let the centre of the circle be C
mRQ=157 (marked)
The angle at the centre of a circle standing on an arc is twice any angle at the circumference, standing on the same arc. So <SCR=2(SQR)=2(46)=92. mSR=<SCR=92
All the arc measure add up to 360 so:
mSQ+mRQ+mSR=360
mSQ+157+92=360
mSQ=360-249=111