What would happen if M RNA were radio actively labeled instead of polypeptides is that instead of one seeing the DNA passing through all the molecular factories you will instead see just messenger RNA taking code and delivering it to Ribosome. This is mainly found in cytoplasm and Endoplasmic recticulums.
Assumptions:
1. Equilibrium has been reached for the allele proportions
2. Absence of <span>evolutionary influences such as </span>mate choice<span>, </span>mutation<span>, </span>selection<span>, </span>genetic drift<span>, </span>gene flow<span> and </span>meiotic drive<span>.
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Defining L=long stem, l=short stem, and L is dominant over l.
f(x) = frequency of allele x (expressed as a fraction of population)
Then the Hardy-Weinberg equilibrium law applies:
p^2+2pq+q^2=1
where
f(LL)=p^2
f(Ll)=2pq
f(ll)=q^2
Given f(ll)=0.35=q^2, we have
q=sqrt(0.35)=0.591608
p=1-q=0.408392
=>
f(Ll)
=2pq
=2*0.408392*0.591608=0.483216
= proportion of heterozygous population
Answer: percentage of heterozygous population is 48.32%
The term applied when water passes through a selectively permeable membrane from an area of high to low concentration is called osmosis. Osmotic pressure is defined as the amount of external pressure that is required to stop the net movement of the solution across the semi permeable membrane. In terms of biology, osmosis has great importance as most of the membranes in our body are semi permeable. Permeability depends on several factors such as charge, solubility, solute size and chemistry. Osmosis is the process that provides the primary means through which water travels in and out of the cells.
