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natali 33 [55]
4 years ago
7

Use long division to find a repeated decimal equivalency for the fraction. This is a question that my teacher gave me for pre al

gebra anyone know how to awnser it
Mathematics
1 answer:
Dafna11 [192]4 years ago
6 0
Take the fraction. Divide the top number by the bottom number. (That's what a fraction means.). Some fractions will produce a decimal that goes on and on and never ends. Some fractions produce a decimal that ends. Some examples that make repeating decimals are: 1/3, 1/7, 1/9, 1/11.
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Please help me thank you
Reptile [31]

Answer:

y \geqslant  \frac{1}{4} x - 1

4 \times y \geqslant  \frac{1}{4}  \times 4x - 4 \times 1

4y \geqslant x - 4

4y + x \geqslant  - 4

5yx \geqslant  - 4

yx \geqslant  - 4 - 5

yx \geqslant  - 9

you're welcome I think I don't really know whether I'm finding x or y or yx

7 0
3 years ago
David has counters. Lisa has 5 more counters than David. Samia has 4 times as many counters as David. The total number of counte
s2008m [1.1K]

Answer:

if 'c' equals number of counters, the answer is 6c + 5

Step-by-step explanation:

david has 'c'

lisa has '5+c'

samia has '4c'

add all terms together:  c + 5 + c + 4c = 6c + 5

3 0
3 years ago
30 Points please answer quickly!!!!! James did an experiment. He started out with 640 bacteria cells. He found that the growth r
Marrrta [24]

Answer:

2327.49 ---> 25 hrs

starting plot points (0,640) and ending (25, 2327.49)

Step-by-step explanation:

b = 640

r = 5.3% = 0.053

t = 25

y = 640 ( 1 + 0.053)^25

y = 640 ( 1.053)^25

y = 2327.49 ---> 25 hrs

starting plot points (0,640) and ending (25, 2327.49)

4 0
3 years ago
Find two consecutive integers such that 3 times larger exceeds twice the smaller by 34
Katen [24]

Answer:

x - a smaller number

(x+1) - a larger number

3(x+1) - 2x = 34

3x + 3 - 2x = 34

x= 31

(x+1) = 32

Step-by-step explanation:

7 0
3 years ago
6-2x=y 14+3x=y plzzz helllllllllllllllp
pashok25 [27]

Answer:

(- \frac{8}{5}, \frac{46}{5} )

Step-by-step explanation:

Given the2 equations

6 - 2x = y → (1)

14 + 3x = y → (2)

Substitute y = 14 + 3x into (1)

6 - 2x = 14 + 3x ( subtract 3x from both sides )

6 - 5x = 14 ( subtract 6 from both sides )

- 5x = 8 ( divide both sides by - 5 )

x = - \frac{8}{5}

Substitute x = - \frac{8}{5} into either of the 2 equations for the corresponding value of y

Substituting into (1)

y = 6 - 2(- \frac{8}{5} ) = \frac{30}{5} + \frac{16}{5} = \frac{46}{5}

solution is ( - \frac{8}{5}, \frac{46}{5} )

8 0
3 years ago
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