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3 years ago

Two inequalities connected by and or or.

Mathematics

1 answer:

Bumek [7]3 years ago

7 0

For example- Are you introverted or extroverted? Would you like xyz and or lmn?

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Solve this equation 4y+228=352

statuscvo [17]

4y + 228 = 352

4y = 352 - 228

4y = 124
--- ----
4 4

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| y = 31 |
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hope this helps

8 0

3 years ago

Read 2 more answers

Identify the expression equivalent to 4(x + x + 7) − 2x + 8 − 4 by substituting x = 1 and x = 2. 6x + 11 3(x + 7) 2(3x + 16) 3x

sveta [45]

2(3x+16)

Step-by-step explanation:

Identify the expression equivalent to 4(x + x + 7) − 2x + 8 − 4

4(x + x + 7) − 2x + 8 − 4

When x=1 , the expression becomes 4(1+1+7)-2(1)+8-4=38

When x=2 , the expression becomes 4(2+2+7)-2(1)+8-4=44

Plug in x=1 and check with each expression

6x + 11 =6(1) +11= 16

3(x + 7) = 3(1+7)= 3(8)= 24

2(3x + 16) = 2(3(1)+16)= 38 , we got same answer when x=1, now check with x=2

2(3x + 16) = 2(3(2)+16)= 44

3x + 16= 3+16= 19

5 0

4 years ago

Point C is on line segment \overline{BD} BD . Given CD=x,CD=x, BC=5x-5,BC=5x−5, and BD=2x+7,BD=2x+7, determine the numerical len

NARA [144]

Answer:

$CD = 3$

Step-by-step explanation:

Given

$CD = x$

$BC = 5x - 5$

$BD = 2x + 7$

Required

Determine CD

Since, C is a point on BD, the relationship between the given parameters is;

$BD = BC + CD$

Substitute the values of BD, BC and CD

$2x + 7 = 5x - 5 + x$

Collect Like Terms

$2x - 5x - x = -5 - 7$

$-4x = -12$

Divide both sides by -4

$\frac{-4x}{-4} = \frac{-12}{-4}$

$x = 3$

To determine the length of CD;

Substitute 3 for x in $CD = x$

Hence;

$CD = 3$

3 0

3 years ago

How to solve −3/4n≤3.

mars1129 [50]

Answer:

n ≥ -4

Step-by-step explanation:

-3/4n ≤ 3

-4/3(-3/4n) ≤ 3(-4/3)

n ≥ -12/3

n ≥ -4

CHECK:

correct

-3/4(-4) ≤ 3

12/4 ≤ 3

3 = 3

correct

-3/4(5) ≤ 3

-15/4 ≤ 3

-3.75 < 3

incorrect

-3/4(1) ≤ 3

-3/4 is not ≤ 3

6 0

3 years ago

HELP ME!! im so stumped. will give brainliest!

Olegator [25]

Answer:

$x=1+\sqrt{3}$ and $x=1-\sqrt{3}$

Step-by-step explanation:

We have been given the parabola with vertex (1, -9) and y intercept at (0, -6).

Now we need to find the x-intercepts of that parabola. So first we begin by finding the equation of parabola using vertex formula:

$y=a\left(x-h\right)^2+k$

Vertex for this formula is given by (h,k)

Compare that with given vertex (1,-9), we get: h=1, k=-9

So plug these into vertex formula:

$y=a\left(x-1\right)^2-9$ ...(i)

Plug given point (0, -6). into (i)

$-6=a\left(0-1\right)^2-9$

$-6=a\left(-1\right)^2-9$

$-6=a\left(1\right)-9$

$-6+9=a$

$3=a$

Plug a=3 into (i)

$y=3\left(x-1\right)^2-9$

Now to find x-intercept, we just plug y=0 and solve for x

$y=3\left(x-1\right)^2-9$

$0=3\left(x-1\right)^2-9$

$9=3\left(x-1\right)^2$

$3=\left(x-1\right)^2$

$\pm \sqrt{3}=x-1$

$1+\pm \sqrt{3}=x$

Hence final answer are

$x=1+\sqrt{3}$ and $x=1-\sqrt{3}$

4 0

3 years ago