D. is the correct answer.
Answer:
A. Calculate vector
B. Update vector of each object
C. Update position of each object
Explanation:
Taking assumption of a system in which the forces are a function of the previous step's final position:
Firstly, we calculate the (vector) forces acting on the objects.
Secondly, Update the (vector) momentum of each object
(note: also update the velocity).
Thirdly, Update the (vector) position of each object.
The other operations are as follows;
i. select (dt),
ii. define mass,
iii. Put down constants,
iv. initialize variables, this would occur before the time-step loop is entered.
H=k+log(a/c)
H-k = log(a/c)
e^{h-k}=a/c
a = ce^{h-k}
Answer:
<u>Protons</u> and <u>Neutrons</u> are the two types of nucleons that make up a nucleus. The <u>electrostatic</u> force exists between <u>protons</u> in the nucleus because of their charge. Because it is repulsive, this force tends to make a nucleus <u>unstable</u>. However, the <u>strong nuclear</u> force acts between protons, between neutrons, and between protons and neutrons. This force helps to make a nucleus <u>stable</u>, because it is always attractive.
Explanation:
The nucleus of an atom contains two types of particles, protons and neutrons. Proton has a positive charge, while neutron has no charge. The protons have a repulsive electrostatic force between each other, due to like charges. Due to this repulsive force protons tend to scatter away making the nucleus unstable. In order to overcome this, a force inside the nucleus binds these protons and neutrons together. This attractive force is called strong nuclear force. This force acts on very short ranges.
