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4 years ago

This is junior year english

Physics

2 answers:

pychu [463]4 years ago

6 0

D. is the correct answer.

Alla [95]4 years ago

6 0

I think the answer is D

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An instrument used to detect the current in a<br> circuit is called

Tanzania [10]

Answer:

Ammeter

Explanation:

An ammeter is used to measure current.

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3 years ago

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A lumberjack (mass = 103 kg) is standing at rest on one end of a floating log (mass = 277 kg) that is also at rest. The lumberja

Lorico [155]

Answer:

Explanation:

Given

mass of lumber jack $m_L=1000 kg$

mass of floating log $m_f=277 kg$

velocity of lumber jack =3.74 m/s (w.r.t. shore)

conserving momentum

Initial momentum=Final momentum

$0=m_L\times 3.74+m_f\times v$

$v=-\frac{1000\times 3.74}{277}$

$v=-13.501 m/s$

(b)For second Log

Conserving Momentum

Initial momentum of log and Lumber jack=Final momentum of log and lumberjack

$m_L\times 3.74=(m_L+m_f)u$

u is final velocity of lumberjack and log

$u=\frac{m_L}{m_L+m_f}\times 3.74$

$u=\frac{1000}{1000+277}=2.92 m/s$

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4 years ago

The law of conservation of momentum states that __________.

dmitriy555 [2]

Answer:

The law of conservation of momentum states that, in the absence of an external force, the momentum of a system remains unchanged.

Explanation:

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2 years ago

What is the gravitational acceleration close to the surface of a planet with a mass of 9ME and radius of 3RE, where ME and RE ar

Papessa [141]

Answer:

9.78 m/s²

Explanation:

To solve this, we use the gravitational formula

g = GM/r², where

g = acceleration due to gravity

G = gravitational constant

M = mass of the planet

r = radius of the planet

From the question, we got that the mass of the planet is

M = 9ME, where ME = 5.95*10^24

M = 9 * 5.95*10^24

M = 5.355*10^25 kg

Also, the Radius of the planet, R = 3RE, where RE = 6.37*10^6

R = 3 * 6.37*10^6

R = 1.911*10^7 m

On applying the values of both R and M to the equation, we get

g = GM/r²

g = (6.67*10^-11 * 5.355*10^25) / (1.911*10^7)²

g = 3.57*10^15/3.65*10^14

g = 9.78 m/s²

Therefore, the acceleration due to gravity on the planet is 9.78 m/s²

Please vote brainliest if it helped you <3

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3 years ago

A man attempts to push a 19.8 kg crate across a warehouse floor. He slowly increases the force until the crate starts to move at

VARVARA [1.3K]

Answer:

μ = 0.18

Explanation:

Let's use Newton's second Law, the coordinate system is horizontal and vertical

Before starting to move the box

Y axis

N-W = 0

N = W = mg

X axis

F -fr = 0

F = fr

The friction force has the formula

fr = μ N

fr = μ m g

At the limit point just before starting the movement

F = μ m g

μ = F / m g

calculate

μ = 34.8 / (19.8 9.8)

μ = 0.18

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3 years ago

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