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Dima020 [189]
3 years ago
10

The brakes of an automobile can decelerate it at -4.7m/s^2. If the automobile is traveling at the rate of 31.0m/s How far will i

t travel after the brakes are applied before it stops?
Please help!!!
Physics
1 answer:
OleMash [197]3 years ago
6 0

Answer:

204.5 m

Explanation:

a = v \ t

t = v \ a

t = 31 \ 4.7 = 6.6s

v = d \ t

d = v * t

d = 31 * 6.6

d= 204.5 meters

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Two parallel conducting plates are connected to a constant voltage source. The magnitude of the electric field between the plate
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Answer:

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Explanation:

Given:

Original magnitude of electric field (E₀) = 2388 N/C

Original voltage = 'V' (Assume)

Original separation between the plates = 'd' (Assume)

Now, new voltage is three times original voltage. So, V_n=3V

New distance is 1/5 the original distance. So, d_n=\dfrac{d}{5}

Now, electric field between the parallel plates originally is given as:

E_0=\frac{V}{d}=2388\ N/C

Let us find the new electric field based on the above formula.

E_n=\frac{V_n}{d_n}\\\\E_n=\frac{3V}{\frac{d}{5}}\\\\E_n=15(\frac{V}{d})

Now, \frac{V}{d}=2388\ N/C. So,

E_n=15\times 2388=35820\ N/C

Therefore, the magnitude of the new electric field is 35820 N/C.

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