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Dima020 [189]
3 years ago
10

The brakes of an automobile can decelerate it at -4.7m/s^2. If the automobile is traveling at the rate of 31.0m/s How far will i

t travel after the brakes are applied before it stops?
Please help!!!
Physics
1 answer:
OleMash [197]3 years ago
6 0

Answer:

204.5 m

Explanation:

a = v \ t

t = v \ a

t = 31 \ 4.7 = 6.6s

v = d \ t

d = v * t

d = 31 * 6.6

d= 204.5 meters

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4) Explain which electric charges attract and which electric charges repel (push away)
DaniilM [7]

Explanation:

According to the fundamental law of electrostatics, like charges which are ( only positive or only negative charges) repel while unlike charges which are ( positive and negative charges ) attract each other.

that is: ( +++++ ++++++) they repel

while ( +++++++ ———) they attract

7 0
3 years ago
Two dogs are pulling on a rope in opposite directions. The dog in the left pulls with a force of 10 N, while the dog in the righ
hodyreva [135]

Answer:

Dog on the right.

Explanation:

Dog on the left is pulling 10N. The dog on the right is pulling at 12N. So the dog on the right is pulling more. Hope this helps :)))

4 0
3 years ago
Read 2 more answers
A uniform continuous line charge with net positive charge Q and length L lies on the x-axis from −L2 to +L2. This problem asks a
irakobra [83]

Answer:

(C) zero (there is no net horizontal component of the E-field)

Explanation:

If we subdivide the bar into small pieces, each piece (dx) contains a charge (dq), the electric field of each piece is equivalent to the field of a punctual electric charge, and has a direction as shown in the attached figure. For each piece (dx) in the negative axis there is another symmetric piece (dx) in the positive axis, and as we see in the figure for symmetry the sum of their electric fields gives a resultant in the Y axis (because its components in X are cancelled by symmetry).

Then the resultant of the electric field will be only in Y.

(C) zero (there is no net horizontal component of the E-field)

5 0
3 years ago
. A 65 kg climber on top of Mt. Everest (8800 m high). How much Pontential Energy does he have?
Kruka [31]

Answer:

He has 5,609,404 J of potential energy

Explanation:

P.E. = M*G*H

65 * 9.8^2 * 8800

7 0
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What will happen to the force felt between two charged objects if the distance between them is 1/3rd of the original distance
kenny6666 [7]

Answer:

New force = 9(initial force)

Explanation:

The force between two charges is given by :

F=\dfrac{kq_1q_2}{r^2}

Where

d is the original distance

Let d' is the new distance such that, r' = r/3

New force,

F'=\dfrac{kq_1q_2}{r'^2}\\\\F'=\dfrac{kq_1q_2}{(\dfrac{r}{3})^2}\\\\F'=9\times \dfrac{kq_1q_2}{r^2}\\\\F'=9F

So, the new force becomes 9 times the initial force.

4 0
3 years ago
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