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Anna [14]
3 years ago
8

the wireless cafe charges $5.40 for 45 minutes of internet access. how much money doe the wireless cafe charge per minute

Mathematics
1 answer:
ki77a [65]3 years ago
8 0
5.40 divided by 45 = 0.12

The cafe charges 12 cents per minute.
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Does the residual plot indicate that a line is a good model for predicting the height of girls from their ages? Explain.
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A plot of residuals (vertical deviations from the regression line) shows the errors or lack of fit, so it would indicate a good fit if the residuals are small, vs. over fit if they are large. Due to age related growth short pre teen, and a plateau after age 21, I would expect a linear regression would offer estimate age 5.5 years.
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3 years ago
A particle moves along a line so that its position at any time t &gt; 0 is given by the function s(t) = - t3 + 7t2 - 14t +8 wher
eimsori [14]

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s(5) = -12

Step-by-step explanation:

s(t) = - t³ + 7t² - 14t +8

Find the displacement during the first 5 seconds.

When t = 5

s(t) = - t³ + 7t² - 14t +8

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4 0
3 years ago
The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and unive
gtnhenbr [62]

Answer: (0.8468, 0.8764)

Step-by-step explanation:

Formula to find the confidence interval for population proportion is given by :-

\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where \hat{p}  = sample proportion.

z* = Critical value

n= Sample size.

Let p be the true proportion of GSU Juniors who believe that they will, immediately, be employed after graduation.

Given : Sample size = 3597

Number of students  believe that they will find a job immediately after graduation= 3099

Then,  \hat{p}=\dfrac{3099}{3597}\approx0.8616

We know that , Critical value for 99% confidence interval = z*=2.576  (By z-table)

The 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation will be

0.8616\pm(2.576)\sqrt{\dfrac{0.8616(1-0.8616)}{3597}}

0.8616\pm (2.576)\sqrt{0.0000331513594662}

\approx0.8616\pm0.0148\\\\=(0.8616-0.0148,\ 0.8616+0.0148)=(0.8468,\ 0.8764)

Hence, the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. = (0.8468, 0.8764)

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