Given:
4log1/2^w (2log1/2^u-3log1/2^v)
Req'd:
Single logarithm = ?
Sol'n:
First remove the parenthesis,
4 log 1/2 (w) + 2 log 1/2 (u) - 3 log 1/2 (v)
Simplify each term,
Simplify the 4 log 1/2 (w) by moving the constant 4 inside the logarithm;
Simplify the 2 log 1/2 (u) by moving the constant 2 inside the logarithm;
Simplify the -3 log 1/2 (v) by moving the constant -3 inside the logarithm:
log 1/2 (w^4) + 2 log 1/2 (u) - 3 log 1/2 (v)
log 1/2 (w^4) + log 1/2 (u^2) - log 1/2 (v^3)
We have to use the product property of logarithms which is log of b (x) + log of b (y) = log of b (xy):
Thus,
Log of 1/2 (w^4 u^2) - log of 1/2 (v^3)
then use the quotient property of logarithms which is log of b (x) - log of b (y) = log of b (x/y)
Therefore,
log of 1/2 (w^4 u^2 / v^3)
and for the final step and answer, reorder or rearrange w^4 and u^2:
log of 1/2 (u^2 w^4 / v^3)
Answer:
The expression is
![.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ \ C \ \ \ \ \ T\\M = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{284}&{483}&{410}\\{597}&{551}&{233}{2}}\\\end{array}\right]](https://tex.z-dn.net/?f=.%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20B%20%5C%20%20%20%5C%20%5C%20%5C%20%5C%20%5C%20C%20%5C%20%5C%20%5C%20%5C%20%5C%20T%5C%5CM%20%3D%20%5Cleft%20%5C%20%20NYC%7D%20%5Catop%20%7BLA%7D%7D%20%5Cright.%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B284%7D%26%7B483%7D%26%7B410%7D%5C%5C%7B597%7D%26%7B551%7D%26%7B233%7D%7B2%7D%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
From the question we are told that
The number of each items made in the month of January[J] is
![.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ C \ \ \ \ \ \ T\\J = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{144}&{474 }&{274}\\{598}&{572}&{302}\\\end{array}\right]](https://tex.z-dn.net/?f=.%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20B%20%5C%20%20%5C%20%5C%20%5C%20%5C%20C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20T%5C%5CJ%20%3D%20%5Cleft%20%5C%20%20NYC%7D%20%5Catop%20%7BLA%7D%7D%20%5Cright.%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B144%7D%26%7B474%20%7D%26%7B274%7D%5C%5C%7B598%7D%26%7B572%7D%26%7B302%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The number of each items made in the month of February[F] is
![.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ C \ \ \ \ \ \ T\\J = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{ 424}&{492}&{546}\\{596 }&{530}&{164}\\\end{array}\right]](https://tex.z-dn.net/?f=.%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20B%20%5C%20%20%5C%20%5C%20%5C%20%5C%20C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20T%5C%5CJ%20%3D%20%5Cleft%20%5C%20%20NYC%7D%20%5Catop%20%7BLA%7D%7D%20%5Cright.%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B%20424%7D%26%7B492%7D%26%7B546%7D%5C%5C%7B596%20%7D%26%7B530%7D%26%7B164%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Generally given that the production for March of all products at all locations was the average of the January and February production then the number of each items made in the month of March[M] is
![.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ \ \ \ \ \ \ \ \ C \ \ \ \ \ \ \ \ \ \ \ T\\M = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{\frac{144 +424}{2}}&{\frac{474 +492}{2}}&{\frac{274 +546}{2}}\\{\frac{598 +596}{2}}&{\frac{572 +530}{2}}&{\frac{302+164}{2}}\\\end{array}\right]](https://tex.z-dn.net/?f=.%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20B%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20T%5C%5CM%20%3D%20%5Cleft%20%5C%20%20NYC%7D%20%5Catop%20%7BLA%7D%7D%20%5Cright.%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B%5Cfrac%7B144%20%2B424%7D%7B2%7D%7D%26%7B%5Cfrac%7B474%20%2B492%7D%7B2%7D%7D%26%7B%5Cfrac%7B274%20%2B546%7D%7B2%7D%7D%5C%5C%7B%5Cfrac%7B598%20%2B596%7D%7B2%7D%7D%26%7B%5Cfrac%7B572%20%2B530%7D%7B2%7D%7D%26%7B%5Cfrac%7B302%2B164%7D%7B2%7D%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=>
a=2 b=3 and c=4. then,
<em>a2+2abc+b2+c2</em>
<em>a2+2abc+b2+c2</em><em>=</em><em> </em><em>2</em><em>^</em><em>2</em><em>+</em><em>2</em><em>×</em><em>2</em><em>×</em><em>3</em><em>×</em><em>4</em><em>+</em><em>3</em><em>^</em><em>2</em><em>+</em><em>4</em><em>^</em><em>2</em>
<em>(</em><em>replace</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>a</em><em>,</em><em> </em><em>b</em><em>,</em><em> </em><em>c</em><em> </em><em>by</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em> </em><em>respectively</em><em> </em><em>tgen</em><em> </em><em>solve</em><em>)</em>
<em>=</em><em> </em><em>4</em><em>+</em><em>4</em><em>8</em><em>+</em><em>9</em><em>+</em><em>1</em><em>6</em>
<em>=</em><em> </em><em>7</em><em>7</em><em>…</em><em>…</em><em>…</em><em>…</em><em>…</em><em>…</em>
<em> </em><em>Therefore</em><em>,</em><em> </em><em>7</em><em>7</em><em> </em><em>is</em><em> </em><em>correct</em><em> </em><em>answer</em><em>.</em>
Answer-
y=-2x+2
It starts at +2 so that is the b
And -2x is how you move so that is the m
That's how I was taught and how I remember it lol hope it helped ik it wasn't the best its 12 am here soo I be tired
