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3 years ago

If a=2, b=3 and c=4 then find the numerical value of a2+2abc+b2+c2

Mathematics

1 answer:

qaws [65]3 years ago

7 0

a=2 b=3 and c=4. then,

a2+2abc+b2+c2

a2+2abc+b2+c2= 2^2+2×2×3×4+3^2+4^2

(replace value of a, b, c by2,3,4 respectively tgen solve)

= 4+48+9+16

= 77………………

Therefore, 77 is correct answer.

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Step-by-step explanation:

we know that

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Remember that

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That means ------> For x=0 the value of f(x) is equal to 60

substitute the value of x and the value of y in the function and solve for a

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$60=a(6)(5)(1)$

$60=30a$

$a=2$

$f(x)=2(x+6)(x+5)(x+1)$

Applying the distributive property

Convert to expanded form

$f(x)=2(x+6)(x+5)(x+1)\\\\f(x)=2(x+6)(x^{2}+x+5x+5)\\\\f(x)=2(x+6)(x^{2}+6x+5)\\\\f(x)=2(x^{3}+6x^{2}+5x+6x^{2}+36x+30)\\\\f(x)=2x^{3}+24x^{2}+82x+60$

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3 years ago

If a=2, b=3 and c=4 then find the numerical value of a2+2abc+b2+c2​

If a=2, b=3 and c=4 then find the numerical value of a2+2abc+b2+c2