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Fed [463]
3 years ago
9

If a=2, b=3 and c=4 then find the numerical value of a2+2abc+b2+c2​

Mathematics
1 answer:
qaws [65]3 years ago
7 0

a=2 b=3 and c=4. then,

<em>a2+2abc+b2+c2</em>

<em>a2+2abc+b2+c2</em><em>=</em><em> </em><em>2</em><em>^</em><em>2</em><em>+</em><em>2</em><em>×</em><em>2</em><em>×</em><em>3</em><em>×</em><em>4</em><em>+</em><em>3</em><em>^</em><em>2</em><em>+</em><em>4</em><em>^</em><em>2</em>

<em>(</em><em>replace</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>a</em><em>,</em><em> </em><em>b</em><em>,</em><em> </em><em>c</em><em> </em><em>by</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em> </em><em>respectively</em><em> </em><em>tgen</em><em> </em><em>solve</em><em>)</em>

<em>=</em><em> </em><em>4</em><em>+</em><em>4</em><em>8</em><em>+</em><em>9</em><em>+</em><em>1</em><em>6</em>

<em>=</em><em> </em><em>7</em><em>7</em><em>…</em><em>…</em><em>…</em><em>…</em><em>…</em><em>…</em>

<em> </em><em>Therefore</em><em>,</em><em> </em><em>7</em><em>7</em><em> </em><em>is</em><em> </em><em>correct</em><em> </em><em>answer</em><em>.</em>

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Find the sum. Write your answer in simplest form.
Masteriza [31]

Answer:

19/20

Step-by-step explanation:

write all numerators above the common denominator 20

14+5/20

19/20

4 0
3 years ago
The height h(n) of a bouncing ball is an exponential function of the number n of bounces.
Digiron [165]

Answer:

The height of a bouncing ball is defined by h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}.

Step-by-step explanation:

According to this statement, we need to derive the expression of the height of a bouncing ball, that is, a function of the number of bounces. The exponential expression of the bouncing ball is of the form:

h = h_{o}\cdot r^{n-1}, n \in \mathbb{N}, 0 < r < 1 (1)

Where:

h_{o} - Height reached by the ball on the first bounce, measured in feet.

r - Decrease rate, no unit.

n - Number of bounces, no unit.

h - Height reached by the ball on the n-th bounce, measured in feet.

The decrease rate is the ratio between heights of two consecutive bounces, that is:

r = \frac{h_{1}}{h_{o}} (2)

Where h_{1} is the height reached by the ball on the second bounce, measured in feet.

If we know that h_{o} = 6\,ft and h_{1} = 4\,ft, then the expression for the height of the bouncing ball is:

h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}

The height of a bouncing ball is defined by h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}.

5 0
3 years ago
Read 2 more answers
Please help, thank you :)
wolverine [178]

Answer:

y^6

Step-by-step explanation:

\frac{y}{1} \times   \frac{{y}^{5} }{1}

=

{y}^{6}

7 0
2 years ago
Which equation has a slope
Dominik [7]
All the choices are in the slope-intercept form where,

y=mx+b

so, the number before the x is the slope. The given slope is -34. We just have to look for the -34 number before the x. So mong the choices, it is the letter a choice that has the slope -34. So the answer is A.
7 0
3 years ago
Read 2 more answers
Harrison Water Sports has two retail outlets: Seattle and Portland. The Seattle store does 60 percent of the total sales in a ye
Anna11 [10]

Answer: P = 0.75

Step-by-step explanation:

Hi!

The sample space of this problems is the set of all the possible sales. It is divided in the disjoint sets:

S_s = {\text{sales made in Seattle }}\\S_p={\text {sales made in Portland}}

We have also the set of sales of boat accesories S_b, the colored one in the image.

We are given the data:

P(S_s) = 0.6\\P(S_b | S_s) = \frac{P(S_b\bigcap S_s)}{P(S_s)}=0.4\\P(S_b|S_p) =\frac{P(S_b\bigcap S_p)}{P(S_p)}=0.2

From these relations you can compute the probabilities of the intersections colored in the image:

pink\;set:\;P(S_b \bigcap S_s) =0.6*0.4=0.24\\blue\;set\;:P(S_b \bigcap S_p)=(1-0.6)*0.2 =0.08

You are asked about the conditional probability:

P(S_s|S_b) = \frac{P(S_s \bigcap S_b)}{P(S_b)}

To calculate this, you need  P(S_b) . In the image you can see that the set S_b is the union of the two disjoint pink and blue sets. Then:

P(S_b)=P((S_b \bigcap S_s)\bigcup(S_b \bigcap S_p)) = 0.24 + 0.08 = 0.32

Finally:

P(S_s|S_b) = \frac{0.24}{0.32}=0.75

4 0
3 years ago
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