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3 years ago

If a=2, b=3 and c=4 then find the numerical value of a2+2abc+b2+c2

Mathematics

1 answer:

qaws [65]3 years ago

7 0

a=2 b=3 and c=4. then,

a2+2abc+b2+c2

a2+2abc+b2+c2= 2^2+2×2×3×4+3^2+4^2

(replace value of a, b, c by2,3,4 respectively tgen solve)

= 4+48+9+16

= 77………………

Therefore, 77 is correct answer.

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If a=2, b=3 and c=4 then find the numerical value of a2+2abc+b2+c2​

If a=2, b=3 and c=4 then find the numerical value of a2+2abc+b2+c2