<u><em>To cover a rectangular region of her yard, Penny needs at least 170.5 square feet of sod. The length of the region is 15.5 feet. What are the possible widths of the region?</em></u>
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<u><em>L=length=15.5 ft; W=width; A=area=>170.5 sq ft</em></u>
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<u><em>L*W=>170.5 sq ft Divide each side by L</em></u>
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<u><em>W=>170.5 sq ft/L</em></u>
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<u><em>W=>170.5 sq ft/15.5 ft=>11 feet</em></u>
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ANSWER: To cover at least 170.5 sq ft. the width must be at least 11 feet.
<h2><em><u>
Brainly pls</u></em></h2>
Answer:
x = 45/17
Step-by-step explanation:
We can move all x to 1 side and all the numbers to another. You can add 8.7 on both sides and get that 2.3x = 0.8x + 4.5. Next, we subtract by 0.8x on both sides to get that 1.7x = 4.5, where we can then divide by 17/10 on both sides to get that x is equal to 45/10 * 10/17, so that means that x = 45/17.
Given that PQ and RS are drawn with KL as tranversal intersecting PQ at M and RS at point N. Angle QMN is congruent to angle LNS because they are alternate to each other. The theorem that Kari can use to show that the meansure of QML is supplementary to the measure of angle SNK is Alternate Exterior Angles Theorem.
This is because angle KNR is equal to QML by alternate exterior angles theorem so is angle MLP and SNK
There are 9 owners and 11 dogs
9×2=18
11×4=44
44+18=62
Systems of linear equations can only have 0, 1, or an infinite number of solutions. These two lines cannot intersect twice. The correct answer is that the system has one solution.
