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Artist 52 [7]
4 years ago
10

Help I need answers it's due today please help as fast as possible

Mathematics
1 answer:
tangare [24]4 years ago
6 0
Idk exactly what they want but heres what i would put
1. Acute, XYZ, ZYX
2. PQR, RQP, RQS
3.  i think its at 130 degrees
4. BEH, CFI
5. EBH, FCI
6. 92 degrees
7. 44 degrees
8. 55 degrees
9. 2x-18= 4x 
                +2x
= -18=6x
      /6
= -3x is the answer sorry had to do the work dont have paper
10. EFG= acute 
the whole ferris wheel isnt there if u get a better pic of it ill help u
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9
iogann1982 [59]
Okay thanks for letting me know I love you love love bye
4 0
3 years ago
The base of a triangular prism is an isosceles right triangle with a hypotenuse of
Setler [38]
SA= Lateral Area + Area (of base)

Lateral area = perimeter of base x height

An isosceles triangle has two congruent base segments. The hypotenuse of an isosceles right triangle is (length of base segment) x (the square root of 2). I did the math for you (shown above) to get 5 as a base.

So 5 + 5 + square root of 50 is your perimeter

Multiply the perimeter times your height (8) and you get the lateral area.

Add your lateral area to the base area (triangle = 1/2 bh)

LA = 136.568...
Area of Triangle base = 12.5

Surface area = 149.068... square cm

6 0
3 years ago
Read 2 more answers
1. Suppose you invest $1000 at an annual interest rate of 4% compounded continuously. How much will you
BlackZzzverrR [31]
You take the 4% and multiply that by eight then you get 0.32 and you multiply that by 1000 and you get 320.00
4 0
4 years ago
A mixture of concrete is made up of sand and cement in the ratio of 5:3.How many cubic centimeters of sand is needed to make 160
bazaltina [42]

Answer: 100\ cm^3

Step-by-step explanation:

Given

The ratio of mixture of sand and cement is 5:3

If the total volume of mixture is 160\ cm^3

Suppose there is 5x and 3x cubic centimeter of sand and cement respectively i.e.

\Rightarrow 5x+3x=160\\\Rightarrow 8x=160\\\Rightarrow x=20\ cm^3

Sand 5x=5\times 20=100\ cm^3

So, there is 100\ cm^3 of sand in the mixture

3 0
3 years ago
Find the equation of the line parallel to y=2x+1 that contains point (14,3)
Sophie [7]

First of all, remember what the equation of a line is:

y=mx+b

Where: 

m=slope

b=y-intercept.

Given this information, we can start by plugging in what we know, we are given the slope which is 2 so we can fill that in, remember m=slope

y=2x+b

To find b, think about what your (x,y) point means:<span>(14,3). When x of the line is 14, y of the line must be 3.

Because we were given the point (14,3) 
</span>

We need to find the value of b.  The 2 is already set and x and y are variables. We want the equation for the line that specifically passes through the given point (14,3).

<span>Plug in for x the number 14 and for y the number 3:
</span>(14,3).
 y=mx+b or 3=2 × 14+b,

solving for b: b=3-(2)(14). b=-25.

<span>Plug that in for b: 
</span><span>y=2x-25
<span>Final answer: 
</span><span>y=2x-25</span></span><span><span>
</span></span>
8 0
3 years ago
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